Improper call to asyncio.Timeout.expired

[rsokl]

Documentation

In this example for using asyncio.Timeout, expired is accessed as an attribute, but it should be called as a method.

I.e. the example should read as:

async def main():
    try:
        # We do not know the timeout when starting, so we pass ``None``.
        async with asyncio.timeout(None) as cm:
            # We know the timeout now, so we reschedule it.
            new_deadline = get_running_loop().time() + 10
            cm.reschedule(new_deadline)

            await long_running_task()
    except TimeoutError:
        pass

    if cm.expired():  # <---- I CHANGED THIS TO BE A METHOD CALL
        print("Looks like we haven't finished on time.")

Linked PRs

• gh-101498 : Updated Doc/library/asyncio-task.rst#timeout #101499
• [3.11] gh-101498 : Fix asyncio.Timeout example in docs (GH-101499) #101501