[base] Remove base::conjunction

Use C++17's std::conjunction instead.

R=leszeks@chromium.org

Bug: v8:12425
Change-Id: I004a1bb4fe1b09f441f8822075a72fd20fc90fec
Reviewed-on: https://chromium-review.googlesource.com/c/v8/v8/+/3570429
Reviewed-by: Leszek Swirski <leszeks@chromium.org>
Commit-Queue: Clemens Backes <clemensb@chromium.org>
Cr-Commit-Position: refs/heads/main@{#79803}

src/base/once.h

@@ -93,7 +93,7 @@ inline void CallOnce(OnceType* once, std::function<void()> init_func) {
 }
 
 template <typename... Args, typename = std::enable_if_t<
-                                conjunction<std::is_scalar<Args>...>::value>>
+                                std::conjunction_v<std::is_scalar<Args>...>>>
 inline void CallOnce(OnceType* once,
                      typename FunctionWithArgs<Args...>::type init_func,
                      Args... args) {

src/base/template-utils.h

@@ -89,15 +89,6 @@ constexpr bool all(Args... rest) {
   return fold(std::logical_and<>{}, true, rest...);
 }
 
-// Corresponds to C++17's std::conjunction
-template <class...>
-struct conjunction : std::true_type {};
-template <class B>
-struct conjunction<B> : B {};
-template <class B, class... Bn>
-struct conjunction<B, Bn...>
-    : std::conditional_t<bool(B::value), conjunction<Bn...>, B> {};
-
 }  // namespace base
 }  // namespace v8