06 guide update 02

unlam · Sep 20, 2024 · 8d778cf · 8d778cf
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diff --git a/06FuerzasLigadura/guíaFuerzasLigadura.pdf b/06FuerzasLigadura/guíaFuerzasLigadura.pdf
diff --git a/06FuerzasLigadura/guíaFuerzasLigadura.tex b/06FuerzasLigadura/guíaFuerzasLigadura.tex
@@ -49,7 +49,7 @@
 			\ddot{y}_{2} = \frac{2 g \left(4 m_{1} + m_{p}\right) \left(m_{2} - m_{3}\right)}{4 m_{1} m_{2} + 4 m_{1} m_{3} + 2 m_{1} m_{p} + 16 m_{2} m_{3} + 8 m_{2} m_{p} + 8 m_{3} m_{p} + 3 m_{p}^{2}}
 		\)
 		\item Obtenga las tensiones de ambas cuerdas.
-			Resusltado:\\
+			Resultado:\\
 			\(
 				Q_{1} = \frac{g \left(32 m_{1} m_{2} m_{3} + 12 m_{1} m_{2} m_{p} + 12 m_{1} m_{3} m_{p} + 4 m_{1} m_{p}^{2} + 8 m_{2} m_{3} m_{p} + 3 m_{2} m_{p}^{2} + 3 m_{3} m_{p}^{2} + m_{p}^{3}\right)}{4 m_{1} m_{2} + 4 m_{1} m_{3} + 2 m_{1} m_{p} + 16 m_{2} m_{3} + 8 m_{2} m_{p} + 8 m_{3} m_{p} + 3 m_{p}^{2}}\\
 				Q_{2} = \frac{g m_{3} \left(16 m_{1} m_{2} + 4 m_{1} m_{p} + 4 m_{2} m_{p} + m_{p}^{2}\right)}{4 m_{1} m_{2} + 4 m_{1} m_{3} + 2 m_{1} m_{p} + 16 m_{2} m_{3} + 8 m_{2} m_{p} + 8 m_{3} m_{p} + 3 m_{p}^{2}}