Add remove_continue rule

[jiwonz]

Closes #202

Cases

Case: There are continue and break together in a loop but there are more continue than break

Input

for i = 1, 10 do
	if i % 3 == 0 then
		continue
	end
	if i % 6 == 0 then
		continue
	end
	if i % 9 == 0 then
		continue
	end
	if i % 10 == 0 then
		break
	end
end

Output

for i = 1, 10 do
local __DARKLUA_REMOVE_CONTINUE_break5784919bbab63ddf=false repeat	if i % 3 == 0 then
break	
end
	if i % 6 == 0 then
break	
end
	if i % 9 == 0 then
break	
end
	if i % 10 == 0 then
__DARKLUA_REMOVE_CONTINUE_break5784919bbab63ddf=true break	
end
until true if __DARKLUA_REMOVE_CONTINUE_break5784919bbab63ddf then break end end

Case: There are continue and break together in a loop but there are more break than continue

Input

for i = 1, 10 do
	if i % 3 == 0 then
		break
	end
	if i % 6 == 0 then
		break
	end
	if i % 9 == 0 then
		break
	end
	if i % 10 == 0 then
		continue
	end
end

Output

for i = 1, 10 do
local __DARKLUA_REMOVE_CONTINUE_continue5784919bbab63ddf=false repeat	if i % 3 == 0 then
break	
end
	if i % 6 == 0 then
break	
end
	if i % 9 == 0 then
break	
end
	if i % 10 == 0 then
__DARKLUA_REMOVE_CONTINUE_continue5784919bbab63ddf=true break	
end
until true if not __DARKLUA_REMOVE_CONTINUE_continue5784919bbab63ddf then break end end

Case: There is only continue in a loop

Input

for i = 1, 10 do
	if i % 5 == 0 then
		continue
	end
	print(i)
end

Output

for i = 1, 10 do
repeat	if i % 5 == 0 then
break	
end
	print(i)
until true end

Note

• blake3 used for exit variable name (break_variable_name, continue_variable_name)

TO-DOs

• Add tests for cases where continue and break are mixed.