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use anyNA() instead of any(is.na()) in standalone-type-checks #1756

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use `anyNA()` instead of `any(is.na())`

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use anyNA() instead of any(is.na()) in standalone-type-checks #1756

use `anyNA()` instead of `any(is.na())`
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Codecov / codecov/project succeeded Oct 21, 2024 in 1s

83.40% (-0.04%) compared to 3d48c13

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83.40% (-0.04%) compared to 3d48c13

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