Remove delegate allocation in jitter calculation in FramedClock

[peppy]

Before	After

[bdach]

I am shook that this can be done and be actually correct.

Proof:

$$ \begin{align} \sigma_x &= \frac{\sum_i (x_i - \bar{x})^2}{|x|} = \\ &= \frac{\sum_i (x_i^2 - 2x_i \bar{x} + \bar{x}^2)}{|x|} = \\ &= \frac{\sum_i x_i^2}{|x|} - 2 \bar{x} \frac{\sum_i x_i}{|x|} + \bar{x}^2 \cdot \frac{\sum_i 1}{|x|} = \\ &= \frac{\sum_i x_i^2}{|x|} - 2 \bar{x} \cdot \bar{x} + \bar{x}^2 \cdot \frac{|x|}{|x|} = \\ &= \frac{\sum_i x_i^2}{|x|} - \bar{x}^2 \end{align} $$

wherein $x_i$ are elements of a set, $\bar{x}$ is the mean of the set, and $|x|$ is the cardinality of the set.

I thought there was no way this was gonna work but kept failing to find counterexamples...