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DOC: fix pandas.TimedeltaIndex.to_pytimedelta RT03,SA01 #59914

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Sep 30, 2024
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1 change: 0 additions & 1 deletion ci/code_checks.sh
Original file line number Diff line number Diff line change
Expand Up @@ -100,7 +100,6 @@ if [[ -z "$CHECK" || "$CHECK" == "docstrings" ]]; then
-i "pandas.Timedelta.max PR02" \
-i "pandas.Timedelta.min PR02" \
-i "pandas.Timedelta.resolution PR02" \
-i "pandas.TimedeltaIndex.to_pytimedelta RT03,SA01" \
-i "pandas.Timestamp.max PR02" \
-i "pandas.Timestamp.min PR02" \
-i "pandas.Timestamp.nanosecond GL08" \
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21 changes: 21 additions & 0 deletions pandas/core/arrays/timedeltas.py
Original file line number Diff line number Diff line change
Expand Up @@ -790,6 +790,19 @@ def to_pytimedelta(self) -> npt.NDArray[np.object_]:
Returns
-------
numpy.ndarray
A NumPy ``timedelta64`` object representing the same duration as the
original pandas ``Timedelta`` object. The precision of the resulting
object is in nanoseconds, which is the default
time resolution used by pandas for ``Timedelta`` objects, ensuring
high precision for time-based calculations.

See Also
--------
to_timedelta : Convert argument to timedelta format.
Timedelta : Represents a duration between two dates or times.
DatetimeIndex: Index of datetime64 data.
Timedelta.components : Return a components namedtuple-like
of a single timedelta.

Examples
--------
Expand All @@ -800,6 +813,14 @@ def to_pytimedelta(self) -> npt.NDArray[np.object_]:
>>> tdelta_idx.to_pytimedelta()
array([datetime.timedelta(days=1), datetime.timedelta(days=2),
datetime.timedelta(days=3)], dtype=object)

>>> tidx = pd.TimedeltaIndex(data=["1 days 02:30:45", "3 days 04:15:10"])
>>> tidx
TimedeltaIndex(['1 days 02:30:45', '3 days 04:15:10'],
dtype='timedelta64[ns]', freq=None)
>>> tidx.to_pytimedelta()
array([datetime.timedelta(days=1, seconds=9045),
datetime.timedelta(days=3, seconds=15310)], dtype=object)
"""
return ints_to_pytimedelta(self._ndarray)

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