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236.py
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236.py
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'''
Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (where we allow a node to be a descendant of itself).”
Example 1:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 1
Output: 3
Explanation: The LCA of nodes 5 and 1 is 3.
Example 2:
Input: root = [3,5,1,6,2,0,8,null,null,7,4], p = 5, q = 4
Output: 5
Explanation: The LCA of nodes 5 and 4 is 5, since a node can be a descendant of itself according to the LCA definition.
Example 3:
Input: root = [1,2], p = 1, q = 2
Output: 1
Constraints:
The number of nodes in the tree is in the range [2, 105].
-109 <= Node.val <= 109
All Node.val are unique.
p != q
p and q will exist in the tree.
'''
# https://leetcode.com/problems/lowest-common-ancestor-of-a-binary-tree/
import unittest
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
def lowestCommonAncestor(root, p, q):
def dfs(node):
if not node:
return None
if node == p or node == q:
return node
left = dfs(node.left)
right = dfs(node.right)
if left and right:
return node
return left or right
return dfs(root)
class TestLowestCommonAncestor(unittest.TestCase):
def test1(self):
root = TreeNode(3, TreeNode(5, TreeNode(6), TreeNode(2, TreeNode(7), TreeNode(4))), TreeNode(1, TreeNode(0), TreeNode(8)))
p = root.left
q = root.right
self.assertEqual(lowestCommonAncestor(root, p, q), root)
def test2(self):
root = TreeNode(3, TreeNode(5, TreeNode(6), TreeNode(2, TreeNode(7), TreeNode(4))), TreeNode(1, TreeNode(0), TreeNode(8)))
p = root.left
q = root.left.right.right
self.assertEqual(lowestCommonAncestor(root, p, q), p)
def test3(self):
root = TreeNode(1, TreeNode(2), TreeNode(3))
p = root.left
q = root.right
self.assertEqual(lowestCommonAncestor(root, p, q), root)
if __name__ == '__main__':
unittest.main()