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LispKit Enum
Library (lispkit enum)
provides an implementation of enumerated values and sets of enumerated values based on the API defined by R6RS.
Enumerated values are represented by ordinary symbols, while finite sets of enumerated values form a separate type, known as enumeration set. The enumeration sets are further partitioned into sets that share the same universe and enumeration type. These universes and enumeration types are created by the make-enumeration
procedure. Each call to that procedure creates a new enumeration type.
In the descriptions of the following procedures, enum-set ranges over the enumeration sets, which are defined as the subsets of the universes that can be defined using make-enumeration
.
(make-enumeration symbol-list) [procedure]
Argument symbol-list must be a list of symbols. The make-enumeration
procedure creates a new enumeration type whose universe consists of those symbols (in canonical order of their first appearance in the list) and returns that universe as an enumeration set whose universe is itself and whose enumeration type is the newly created enumeration type.
(enum-set-universe enum-set) [procedure]
Returns the set of all symbols that comprise the universe of its argument enum-set, as an enumeration set.
(enum-set-indexer enum-set) [procedure]
Returns a unary procedure that, given a symbol that is in the universe of enum-set, returns its 0-origin index within the canonical ordering of the symbols in the universe; given a value not in the universe, the unary procedure returns #f
.
(let* ((e (make-enumeration '(red green blue)))
(i (enum-set-indexer e)))
(list (i 'red) (i 'green) (i 'blue) (i 'yellow)))
⇒ (0 1 2 #f)
The enum-set-indexer
procedure could be defined as follows using the memq
procedure:
(define (enum-set-indexer set)
(let* ((symbols (enum-set->list (enum-set-universe set)))
(cardinality (length symbols)))
(lambda (x)
(cond ((memq x symbols) =>
(lambda (probe) (- cardinality (length probe))))
(else #f)))))
(enum-set-constructor enum-set) [procedure]
Returns a unary procedure that, given a list of symbols that belong to the universe of enum-set, returns a subset of that universe that contains exactly the symbols in the list. The values in the list must all belong to the universe.
(enum-set->list enum-set) [procedure]
Returns a list of the symbols that belong to its argument, in the canonical order of the universe of enum-set.
(let* ((e (make-enumeration '(red green blue)))
(c (enum-set-constructor e)))
(enum-set->list (c '(blue red))))
⇒ (red blue)
(enum-set-member? symbol enum-set) [procedure]
(enum-set-subset? enum-set1 enum-set2) [procedure]
(enum-set=? enum-set1 enum-set2) [procedure]
The enum-set-member?
procedure returns #t
if its first argument is an element of its second argument, #f
otherwise.
The enum-set-subset?
procedure returns #t
if the universe of enum-set1 is a subset of the universe of enum-set2 (considered as sets of symbols) and every element of enum-set1 is a member of enum-set2. It returns #f
otherwise.
The enum-set=?
procedure returns #t
if enum-set1 is a subset of enum-set2 and vice versa, as determined by the enum-set-subset?
procedure. This implies that the universes of the two sets are equal as sets of symbols, but does not imply that they are equal as enumeration types. Otherwise, #f
is returned.
(let* ((e (make-enumeration '(red green blue)))
(c (enum-set-constructor e)))
(list (enum-set-member? 'blue (c '(red blue)))
(enum-set-member? 'green (c '(red blue)))
(enum-set-subset? (c '(red blue)) e)
(enum-set-subset? (c '(red blue)) (c '(blue red)))
(enum-set-subset? (c '(red blue)) (c '(red)))
(enum-set=? (c '(red blue)) (c '(blue red)))))
⇒ (#t #f #t #t #f #t)
(enum-set-union enum-set1 enum-set2) [procedure]
(enum-set-intersection enum-set1 enum-set2) [procedure]
(enum-set-difference enum-set1 enum-set2) [procedure]
Arguments enum-set1 and enum-set2 must be enumeration sets that have the same enumeration type.
The enum-set-union
procedure returns the union of enum-set1 and enum-set2. The enum-set-intersection
procedure returns the intersection of enum-set1 and enum-set2. The enum-set-difference
procedure returns the difference of enum-set1 and enum-set2.
(let* ((e (make-enumeration '(red green blue)))
(c (enum-set-constructor e)))
(list (enum-set->list (enum-set-union (c '(blue)) (c '(red))))
(enum-set->list
(enum-set-intersection (c '(red green)) (c '(red blue))))
(enum-set->list
(enum-set-difference (c '(red green)) (c '(red blue))))))
⇒ ((red blue) (red) (green))
(enum-set-complement enum-set) [procedure]
Returns enum-set's complement with respect to its universe.
(let* ((e (make-enumeration '(red green blue)))
(c (enum-set-constructor e)))
(enum-set->list (enum-set-complement (c '(red)))))
⇒ (green blue)
(enum-set-projection enum-set1 enum-set2) [procedure]
Projects enum-set1 into the universe of enum-set2, dropping any elements of enum-set1 that do not belong to the universe of enum-set2. If enum-set1 is a subset of the universe of its second, no elements are dropped, and the injection is returned.
(let ((e1 (make-enumeration '(red green blue black)))
(e2 (make-enumeration '(red black white))))
(enum-set->list (enum-set-projection e1 e2))))
⇒ (red black)
(define-enumeration type-name (symbol ...) constructor) [syntax]
The define-enumeration
form defines an enumeration type and provides two macros for constructing its members and sets of its members. A define-enumeration
form is a definition and can appear anywhere any other definition can appear.
type-name is an identifier that is bound as a syntactic keyword; symbol ... are the symbols that comprise the universe of the enumeration (in order).
(
type-name symbol)
checks whether the name of symbol is in the universe associated with type-name. If it is, (
type-name symbol)
is equivalent to symbol. It is a syntax violation if it is not.
constructor is an identifier that is bound to a syntactic form that, given any finite sequence of the symbols in the universe, possibly with duplicates, expands into an expression that evaluates to the enumeration set of those symbols.
(
constructor symbol ...)
checks whether every ... is in the universe associated with type-name. It is a syntax violation if one or more is not. Otherwise (
constructor symbol> ...)
is equivalent to ((enum-set-constructor (
constructor-syntax)) '(
symbol ...))
.
Here is a complete example:
(define-enumeration color (black white purple maroon) color-set)
(color black) ⇒ black
(color purpel) ⇒ error: symbol not in enumeration universe
(enum-set->list (color-set)) ⇒ ()
(enum-set->list
(color-set maroon white)) ⇒ (white maroon)
Some of this documentation is derived from the R6RS specification of hash tables by Michael Sperber, Kent Dybvig, Matthew Flatt, Anton van Straaten, Richard Kelsey, William Clinger, and Jonathan Rees.