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[IMPROVED] Add node48
to stree
#5585
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,110 @@ | ||
// Copyright 2023-2024 The NATS Authors | ||
// Licensed under the Apache License, Version 2.0 (the "License"); | ||
// you may not use this file except in compliance with the License. | ||
// You may obtain a copy of the License at | ||
// | ||
// http://www.apache.org/licenses/LICENSE-2.0 | ||
// | ||
// Unless required by applicable law or agreed to in writing, software | ||
// distributed under the License is distributed on an "AS IS" BASIS, | ||
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. | ||
// See the License for the specific language governing permissions and | ||
// limitations under the License. | ||
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package stree | ||
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// Node with 48 children | ||
// Memory saving vs node256 comes from the fact that the child array is 16 bytes | ||
// per `node` entry, so node256's 256*16=4096 vs node48's 256+(48*16)=1024 | ||
// Note that `key` is effectively 1-indexed, as 0 means no entry, so offset by 1 | ||
// Order of struct fields for best memory alignment (as per govet/fieldalignment) | ||
type node48 struct { | ||
child [48]node | ||
meta | ||
key [256]byte | ||
} | ||
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func newNode48(prefix []byte) *node48 { | ||
nn := &node48{} | ||
nn.setPrefix(prefix) | ||
return nn | ||
} | ||
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func (n *node48) addChild(c byte, nn node) { | ||
if n.size >= 48 { | ||
panic("node48 full!") | ||
} | ||
n.child[n.size] = nn | ||
n.key[c] = byte(n.size + 1) // 1-indexed | ||
n.size++ | ||
} | ||
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func (n *node48) findChild(c byte) *node { | ||
i := n.key[c] | ||
if i == 0 { | ||
return nil | ||
} | ||
return &n.child[i-1] | ||
} | ||
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func (n *node48) isFull() bool { return n.size >= 48 } | ||
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func (n *node48) grow() node { | ||
nn := newNode256(n.prefix) | ||
for c := byte(0); c < 255; c++ { | ||
if i := n.key[c]; i > 0 { | ||
nn.addChild(c, n.child[i-1]) | ||
} | ||
} | ||
return nn | ||
} | ||
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// Deletes a child from the node. | ||
func (n *node48) deleteChild(c byte) { | ||
i := n.key[c] | ||
if i == 0 { | ||
return | ||
} | ||
i-- // Adjust for 1-indexing | ||
last := byte(n.size - 1) | ||
if i < last { | ||
n.child[i] = n.child[last] | ||
for c := byte(0); c <= 255; c++ { | ||
if n.key[c] == last+1 { | ||
n.key[c] = i + 1 | ||
break | ||
} | ||
} | ||
} | ||
n.child[last] = nil | ||
n.key[c] = 0 | ||
n.size-- | ||
} | ||
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// Shrink if needed and return new node, otherwise return nil. | ||
func (n *node48) shrink() node { | ||
if n.size > 16 { | ||
return nil | ||
} | ||
nn := newNode16(nil) | ||
for c := byte(0); c < 255; c++ { | ||
if i := n.key[c]; i > 0 { | ||
nn.addChild(c, n.child[i-1]) | ||
} | ||
} | ||
return nn | ||
} | ||
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// Iterate over all children calling func f. | ||
func (n *node48) iter(f func(node) bool) { | ||
for _, c := range n.child { | ||
if c != nil && !f(c) { | ||
return | ||
} | ||
} | ||
} | ||
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// Return our children as a slice. | ||
func (n *node48) children() []node { | ||
return n.child[:n.size] | ||
} |
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Interesting approach, most of the complexity for a node48 comes from the key handling, this avoids that for a slight increase per node size but with still good savings from child array.