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Correct slew to settle
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hpretl committed Jan 7, 2025
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@@ -92,7 +92,7 @@ so this leaves plenty of margin for additional slow-signal settling due to the l

The small-signal settling (assuming one pole at the bandwidth corner frequency) leads to an approximate settling time (1% error corresponds to $\approx 5 \tau$) of
$$
T_\mathrm{slew} \approx \frac{5}{2 \pi f_\mathrm{c}} = \frac{5}{2 \pi \cdot 1 \cdot 10^{6}} = 0.8\,\mu\text{s}.
T_\mathrm{settle} \approx \frac{5}{2 \pi f_\mathrm{c}} = \frac{5}{2 \pi \cdot 1 \cdot 10^{6}} = 0.8\,\mu\text{s}.
$$
which also checks out.

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