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Makefile: != operator not recognized by syntax highlighting #2

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aeschli opened this issue Oct 23, 2018 · 2 comments
Closed

Makefile: != operator not recognized by syntax highlighting #2

aeschli opened this issue Oct 23, 2018 · 2 comments

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@aeschli
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aeschli commented Oct 23, 2018

From @burianvlastimil on October 22, 2018 9:7

  • VSCode Version:
Version: 1.28.2
Commit: 7f3ce96ff4729c91352ae6def877e59c561f4850
Date: 2018-10-17T00:20:56.183Z
Electron: 2.0.9
Chrome: 61.0.3163.100
Node.js: 8.9.3
V8: 6.1.534.41
Architecture: x64
  • OS Version:

Linux Mint 19 Cinnamon

$ uname -s; uname -m; uname -r
Linux
x86_64
4.15.0-36-generic

Steps to Reproduce:

  1. Open a Makefile
  2. Type:
variable_name != value_assigned_by_shell__some_command

Does this issue occur when all extensions are disabled?: Yes

Note:

  • this operator (!=) is available in both GNU and BSD make

I attach a sample:

vscode != operator not recognized by syntax highlighting

Copied from original issue: microsoft/vscode#61475
@aeschli aeschli mentioned this issue Oct 23, 2018
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@fadeevab
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Got it

fadeevab pushed a commit that referenced this issue Oct 27, 2018
Recognize '!=' as a variable-assignment operator (issue #2)
3d6aeed
@fadeevab
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Fixed: 3d6aeed

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@fadeevab @aeschli