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Use descriptive component names and fix use of ref #2935

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Jan 19, 2022
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Use descriptive component names and fix use of ref #2935

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175c738
Use descriptive component names and fix use of ref
sammy-SC Jan 18, 2022
5ca825f
Remove ambiguity from migrating .measure* example
sammy-SC Jan 18, 2022
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42 changes: 22 additions & 20 deletions docs/new-architecture-library-intro.md
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Original file line number Diff line number Diff line change
Expand Up @@ -111,14 +111,14 @@ While we know that all deprecations are a hassle, this guide is intended to help

Much of the migration work requires a HostComponent ref to access certain APIs that are only attached to host components (like View, Text, or ScrollView). HostComponents are the return value of calls to `requireNativeComponent`. `findNodeHandle` tunnels through multiple levels of component hierarchy to find the nearest native component.

As a concrete example, this code uses `findNodeHandle` to tunnel from `MyComponent` through to the `View` rendered by `MyJSComponent`.
As a concrete example, this code uses `findNodeHandle` to tunnel from `ParentComponent` through to the `View` rendered by `ChildComponent`.

```jsx
class MyComponent extends React.Component<Props> {
_ref: ?React.ElementRef<typeof MyJSComponent>;
class ParentComponent extends React.Component<Props> {
_ref: ?React.ElementRef<typeof ChildComponent>;

render() {
return <MyJSComponent ref={this._captureRef} onSubmit={this._onSubmit} />
return <ChildComponent ref={this._captureRef} onSubmit={this._onSubmit} />
}

_captureRef: (ref) => {
Expand All @@ -134,27 +134,29 @@ class MyComponent extends React.Component<Props> {
}
}

function MyJSComponent(props) {
return (
<View>
<SubmitButton onSubmit={props.onSubmit} />
</View>
);
class ChildComponent extends React.Component<Props> {
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Does the component need to be a class? Generally we prefer functional components in examples if possible.

Ideally it would be nice to provide both examples in tabs like in most of the APIs docs:

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Example with function component is below on line 171.
I will think about it and create a separate PR cc @cortinico

render() {
return (
<View>
<SubmitButton onSubmit={props.onSubmit} />
</View>
);
}
}
```

We can’t convert this call to `this._ref.measure` because `this._ref` is an instance to `MyJSComponent`, which is not a HostComponent and thus does not have a `measure` function.
We can’t convert this call to `this._ref.measure` because `this._ref` is an instance to `ChildComponent`, which is not a HostComponent and thus does not have a `measure` function.

`MyJSComponent` renders a View, which is a HostComponent, so we need to get a reference to `View` instead. There are typically two approaches to get what we need. If the component we need to get the ref from is a function component using `forwardRef` is probably the right choice. If it is a class component with other public methods, adding a public method for getting the ref is an option. Here are examples of those two forms:
`ChildComponent` renders a `View`, which is a HostComponent, so we need to get a reference to `View` instead. There are typically two approaches to get what we need. If the component we need to get the ref from is a function component using `forwardRef` is probably the right choice. If it is a class component with other public methods, adding a public method for getting the ref is an option. Here are examples of those two forms:

### Using `forwardRef`

```jsx
class MyComponent extends React.Component<Props> {
_ref: ?React.ElementRef<typeof MyJSComponent>;
class ParentComponent extends React.Component<Props> {
_ref: ?React.ElementRef<typeof ChildComponent>;

render() {
return <MyJSComponent ref={this._captureRef} onSubmit={this._onSubmit} />
return <ChildComponent ref={this._captureRef} onSubmit={this._onSubmit} />
}

_captureRef: (ref) => {
Expand All @@ -168,7 +170,7 @@ class MyComponent extends React.Component<Props> {
}
}

const MyJSComponent = React.forwardRef((props, forwardedRef) => {
const ChildComponent = React.forwardRef((props, forwardedRef) => {
return (
<View ref={forwardedRef}>
<SubmitButton onSubmit={props.onSubmit} />
Expand All @@ -180,11 +182,11 @@ const MyJSComponent = React.forwardRef((props, forwardedRef) => {
### Using a getter, (note the addition of `getViewRef`)

```tsx
class MyComponent extends React.Component<Props> {
_ref: ?React.ElementRef<typeof MyJSComponent>;
class ParentComponent extends React.Component<Props> {
_ref: ?React.ElementRef<typeof ChildComponent>;

render() {
return <MyJSComponent ref={this._captureRef} onSubmit={this._onSubmit} />
return <ChildComponent ref={this._captureRef} onSubmit={this._onSubmit} />
}

_captureRef: (ref) => {
Expand All @@ -198,7 +200,7 @@ class MyComponent extends React.Component<Props> {
}
}

class MyJSComponent extends React.Component<Props> {
class ChildComponent extends React.Component<Props> {
_ref: ?React.ElementRef<typeof View>;

render() {
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