p2p/discover: fix crash when revalidated node is removed #29864
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lightclient
reviewed
May 28, 2024
|
After looking into this a bit more, I now think the whole idea of tracking the origin list for revalidation requests is wrong. The list a node is contained in can change while a request is in progress. We should just store the current revalidation list in |
lightclient
reviewed
May 28, 2024
lightclient
approved these changes
May 28, 2024
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hi |
This was referenced Jun 5, 2024
18 tasks
jorgemmsilva
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to iotaledger/go-ethereum
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Jun 17, 2024
) In ethereum#29572, I assumed the revalidation list that the node is contained in could only ever be changed by the outcome of a revalidation request. But turns out that's not true: if the node gets removed due to FINDNODE failure, it will also be removed from the list it is in. This causes a crash. The invariant is: while node is in table, it is always in exactly one of the two lists. So it seems best to store a pointer to the current list within the node itself.
maoueh
pushed a commit
to streamingfast/go-ethereum
that referenced
this pull request
Aug 1, 2024
) In ethereum#29572, I assumed the revalidation list that the node is contained in could only ever be changed by the outcome of a revalidation request. But turns out that's not true: if the node gets removed due to FINDNODE failure, it will also be removed from the list it is in. This causes a crash. The invariant is: while node is in table, it is always in exactly one of the two lists. So it seems best to store a pointer to the current list within the node itself.
stwiname
pushed a commit
to subquery/data-node-go-ethereum
that referenced
this pull request
Sep 9, 2024
) In ethereum#29572, I assumed the revalidation list that the node is contained in could only ever be changed by the outcome of a revalidation request. But turns out that's not true: if the node gets removed due to FINDNODE failure, it will also be removed from the list it is in. This causes a crash. The invariant is: while node is in table, it is always in exactly one of the two lists. So it seems best to store a pointer to the current list within the node itself.
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Fixes #29860