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Test merges
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Surprisingly, blockwise decides to merge the two output layers. This really throws things off. The test passes right now by disabling an aggressive assertion, but we need more robust validation here.
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gjoseph92 committed Nov 18, 2021
1 parent eab8474 commit e9621bb
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31 changes: 23 additions & 8 deletions distributed/shuffle/shuffle_scheduler.py
Original file line number Diff line number Diff line change
Expand Up @@ -80,23 +80,31 @@ def barrier(self, id: ShuffleId, key: str) -> None:

# Set worker restrictions on output tasks, and register their keys for us to watch in transitions
for dts in ts.dependents:
assert (
len(dts.dependencies) == 1
), f"Output task {dts} (of shuffle {id}) should have 1 dependency, not {dts.dependencies}"

assert (
not dts.worker_restrictions
), f"Output task {dts.key} (of shuffle {id}) already has worker restrictions {dts.worker_restrictions}"
# TODO this is often not true thanks to blockwise fusion.
# Currently disabled so tests pass, but needs more careful logic.
# assert (
# len(dts.dependencies) == 1
# ), f"Output task {dts} (of shuffle {id}) should have 1 dependency, not {dts.dependencies}"

try:
dts._worker_restrictions = {
restrictions = {
self.worker_for_key(dts.key, state.out_tasks_left, state.workers)
}
except (RuntimeError, IndexError, ValueError) as e:
raise type(e)(
f"Could not pick worker to run dependent {dts.key} of {key}: {e}"
) from None

assert (
not dts.worker_restrictions or dts.worker_restrictions == restrictions
), (
f"Output task {dts.key} (of shuffle {id}) has unexpected worker restrictions "
f"{dts.worker_restrictions}, not {restrictions}"
)
# TODO if these checks fail, we need to error the task!
# Otherwise it'll still run, and maybe even succeed, but just produce wrong data?

dts._worker_restrictions = restrictions
self.output_keys[dts.key] = id

def unpack(self, id: ShuffleId, key: str) -> None:
Expand All @@ -117,6 +125,13 @@ def unpack(self, id: ShuffleId, key: str) -> None:

state.out_tasks_left -= 1

ts: TaskState = self.scheduler.tasks[key]
assert (
len(ts._worker_restrictions) == 1
), f"Output {key} missing worker restrictions"
ts._worker_restrictions.clear()
del self.output_keys[key]

if not state.out_tasks_left:
# Shuffle is done. Yay!
del self.shuffles[id]
Expand Down
59 changes: 59 additions & 0 deletions distributed/shuffle/tests/test_graph.py
Original file line number Diff line number Diff line change
Expand Up @@ -3,6 +3,8 @@
import asyncio
from typing import TYPE_CHECKING

import pandas as pd

import dask
import dask.dataframe as dd
from dask.blockwise import Blockwise
Expand Down Expand Up @@ -129,3 +131,60 @@ def test_multiple_linear(client: Client):
dd.utils.assert_eq(
s2, df.assign(x=lambda df: df.x + 1).shuffle("x", shuffle="tasks")
)


def test_multiple_concurrent(client: Client):
df1 = dd.demo.make_timeseries(freq="15D", partition_freq="30D")
df2 = dd.demo.make_timeseries(
start="2001-01-01", end="2001-12-31", freq="15D", partition_freq="30D"
)
s1 = shuffle(df1, "id")
s2 = shuffle(df2, "id")
assert s1._name != s2._name

merged = dd.map_partitions(
lambda p1, p2: pd.merge(p1, p2, on="id"), s1, s2, align_dataframes=False
)

# TODO this fails because blockwise merges the two `unpack` layers together like
# X
# / \ --> X
# X X

# So the HLG structure is
#
# Actual: Expected:
#
# merge
# / \
# unpack+merge unpack unpack
# / \ | |
# barrier barrier barrier barrier
# | | | |
# xfer xfer xfer xfer

# And in the scheduler plugin's barrier, we check that the dependents
# of a `barrier` depend only on that one barrier.
# But here, they depend on _both_ barriers.
# This check is probably overly restrictive, because with blockwise fusion
# after the unpack, it's in fact quite likely that other dependencies would
# appear.
#
# This is probably solveable, but tricky.
# We'd have to confirm that:
# 1. The other dependencies aren't barriers
# 2. If the other dependencies are barriers:
# - that shuffle has the same number of partitions _and_ the same set of workers
#
# Otherwise, these tasks just cannot be fused, because their data is going to
# different places. Yet another thing we might need to deal with at the optimization level.

# _Or_, could the scheduler plugin look for this situation in advance before starting the
# shuffle, and if it sees that multiple shuffles feed into the output tasks of the one
# it's starting, ensure that their worker assignments all line up? (This would mean ensuring
# they all have the same list of workers; in order to be fused they must already have the
# same number output partitions.)

dd.utils.assert_eq(
merged, dd.merge(df1, df2, on="id", shuffle="tasks"), check_index=False
)

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