implicitly has type 'any' because it does not have a type annotation

[productdevbook]

const LocationSchema = z.object({
  aa: z.object({
    title: z.string(),
  }),
  bb: z.object({
    type: z.literal('Point'),
    coordinates: z.array(z.number()),
  }),
  school: SchoolSchema,
})

const SchoolSchema = z.object({
  title: z.string(),
  address: z.string(),
  locations: z.array(LocationSchema),
})

'LocationSchema' implicitly has type 'any' because it does not have a type annotation and is referenced directly or indirectly in its own initializer.ts(7022)

[JacobWeisenburger]

These might be helpful for you:
Recursive types
Cyclical objects

[santosh-akqa]

Yes but when we extend schema with Recursive types, i.e.

const baseCategorySchema = z.object({
  name: z.string(),
});

type Category = z.infer<typeof baseCategorySchema> & {
  subcategories: Category[];
};

const categorySchema: z.ZodType<Category> = baseCategorySchema.extend({
  subcategories: z.lazy(() => categorySchema.array()),
});

like

const productSchema = categorySchema.extend(....)

we'll get

Property 'extend' does not exist on type 'ZodType<BaseContainer, ZodTypeDef, BaseContainer>'

@JacobWeisenburger Can you suggest any solution for this 🧐