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Update array-and-strings.txt #1

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ca65d0d
Update array-and-strings.txt
KarinAnt Oct 11, 2019
06d1281
Update array-and-strings.txt
KarinAnt Oct 14, 2019
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178 changes: 176 additions & 2 deletions array-and-strings.txt
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Original file line number Diff line number Diff line change
Expand Up @@ -7,6 +7,17 @@ Input: [1, 4, ‘i am a string’, ‘456’]
Output: “Numbers: 2, Strings: 2”

Solution:
function Coun(arr){
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Please name functions based on their purpose: getLongestWord, findNumbersAndSringsCount etc.

var a=0, b=0;
for(let i = 0; i< arr.length; i++){
if(typeof(arr[i])==='number'){
a++;
}else if(typeof(arr[i])==='string'){
b++;
}
}
return {'numbers':a, "strings":b};
}



Expand All @@ -23,6 +34,18 @@ Input: ”Which would be worse - to live as a monster, or to die as a good man?
Output: "monster"

Solution:
function Long(str){
var arr = str.split(/[\s,-]+/);
var max = arr[0].length;
var b = arr[0];
for(let i = 1; i<arr.length; i++){
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Use forEach instead of for

if(max <= arr[i].length){
max = arr[i].length;
b = arr[i];
}
}
return b;
}



Expand All @@ -37,6 +60,15 @@ Input: "[1, 1, 2, -3, 0, 8, 4, 0], 9"
Output: "[]"

Solution:
function Array(arr, n){
var ar1 = [];
for(let i = 0; i < arr.length; i++){
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"filter" is more appropriate in this case

if(arr[i] > n){
ar1.push(arr[i]);
}
}
return ar1;
}



Expand All @@ -50,13 +82,155 @@ Input: 9425
Output: “nine thousand four hundred twenty five”

Solution:

function Num(n){
var a, b;
var ob1 = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine'];
if(String(n).length == 1){
for(let i = 0; i < ob1.length; i++ ){
if(n === i){
return ob1[i];
}
}
}else if(String(n).length == 2){
a = n%10;
n = Math.floor(n/10);
if(n === 1){
if(a === 0){
return "ten";
}else if( a === 1){
return "eleven";
}else if( a === 2){
return "twelve";
}else if(a === 8){
return "eighteen";
}else{
for(let i = 0; i < ob1.length; i++){
if(a === i){
return ob1[i]+'teen';
}
}
}
}else{
for(let i = 1; i < ob1.length; i ++){
if(a === i){
a = ob1[i];
}
}
switch(n){
case 2:
n = 'twenty';
break;
case 3:
n = 'thirty';
break;
case 4:
n = "forty";
break;
case 5:
n = "fifty";
break;
case 6:
n = "sixty";
break;
case 7:
n = "seventy";
break;
case 8:
n = "eighty";
break;
case 9:
n = "ninety";
}
if(a === 0){
return n;
}
return n + " " + a;
}
}else if(String(n).length == 3){
b=Math.floor(n/100);
n = n%100;
for(let i = 0; i < ob1.length; i++){
if(b === i){
b = ob1[i] + " " + "hundred";
}
}
a = n%10;
n = Math.floor(n/10);
if(n === 1){
if(a === 0){
return b + " " + "ten";
}else if( a === 1){
return b + " " + "eleven";
}else if( a === 2){
return b + " " + "twelve";
}else if(a === 8){
return b + " " + "eighteen";
}else{
for(let i = 3; i < ob1.length; i++){
if(a === i){
return b + " " + ob1[i]+'teen';
}
}
}
}else{
for(let i = 1; i < ob1.length; i ++){
if(a === i){
a = ob1[i];
}
}
switch(n){
case 0:
n ='';
break;
case 2:
n = 'twenty';
break;
case 3:
n = 'thirty';
break;
case 4:
n = "forty";
break;
case 5:
n = "fifty";
break;
case 6:
n = "sixty";
break;
case 7:
n = "seventy";
break;
case 8:
n = "eighty";
break;
case 9:
n = "ninety";
}
if(a === 0){
return b + " " + n;
}
return b+ " " + n + " " + a;
}
}
}



5) A left rotation operation on an array shifts each of the array's elements unit to the left. For example,
if 2 left rotations are performed on array [1, 2, 3, 4, 5], then the array would become [3, 4, 5, 1, 2].
if left rotations are performed on array [1, 2, 3, 4, 5], then the array would become [3, 4, 5, 1, 2].

Solution:
function Shi(arr, n){
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Please implement with one or no loops

for(let j = 0; j<n; j++){
let a = arr[0];
for(let i = 1; i <arr.length; i++){
let b = arr[i-1];
arr[i-1] = arr[i];
arr[i]=arr[i-1];
}
arr[arr.length-1] = a;
}
return arr;
}