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[basics] Fixes typos
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dbosk committed Feb 6, 2017
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9 changes: 5 additions & 4 deletions basics/basics.tex
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Expand Up @@ -520,7 +520,7 @@ \subsection{Conditional entropy}
% \end{theorem}
%\end{frame}

\subsection{Informationstäthet och redundans}
\subsection{Information density and redundancy}

\begin{frame}
\begin{definition}
Expand Down Expand Up @@ -626,7 +626,7 @@ \subsection{Information gain}

\begin{remark}
\begin{itemize}
\item \(X' = \{\fcdice{1}, \fcdice{3}, \fcdice{5}\}\)
\item \(X' = \{\fcdice{2}, \fcdice{4}, \fcdice{6}\}\)
\item \(H(\stoch X') = - \sum_{x\in X'} \Pr(\stoch X' = x)\log \Pr(\stoch
X' = x)\)
\item I.e.\ \(- 3 \times \frac{1}{3}\log\frac{1}{3} \approx 1.58\).
Expand All @@ -637,10 +637,11 @@ \subsection{Information gain}
\begin{frame}
\begin{example}[Dice yet again]
\begin{itemize}
\item We learn the die show less than five.
\item We learn the die show less than five, i.e.\ not \fcdice{5} or
\fcdice{6}.
\item This yields
\begin{align*}
-\log\left( 5\times\frac{1}{6}\right) = \log\frac{6}{5}\approx 0.26
-\log\left( 4\times\frac{1}{6}\right) = \log\frac{6}{4}\approx 0.58
\end{align*}
\end{itemize}
\end{example}
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