Merge pull request #1659 from thomaslevesque/fix-dummy-specs

Make wording consistent in DummyCreationSpecs and don't use A.Dummy directly
FakeItEasy · Oct 16, 2019 · 06bb07d · 06bb07d
2 parents b5b6ba5 + 9532287
commit 06bb07d
Showing 1 changed file with 7 additions and 7 deletions.
diff --git a/tests/FakeItEasy.Specs/DummyCreationSpecs.cs b/tests/FakeItEasy.Specs/DummyCreationSpecs.cs
@@ -414,11 +414,11 @@ public void AvoidLongSelfReferentialConstructor(
             "And the class has a two-parameter constructor using its own type"
                 .See(() => new ClassWithLongSelfReferentialConstructor(typeof(object), default));
 
-            "When I create a dummy of the class"
-                .x(() => dummy1 = A.Dummy<ClassWithLongSelfReferentialConstructor>());
+            "When a dummy of the class is requested"
+                .x(() => dummy1 = this.CreateDummy<ClassWithLongSelfReferentialConstructor>());
 
             "And I create another dummy of the class"
-                .x(() => dummy2 = A.Dummy<ClassWithLongSelfReferentialConstructor>());
+                .x(() => dummy2 = this.CreateDummy<ClassWithLongSelfReferentialConstructor>());
 
             "Then the first dummy is not null"
                 .x(() => dummy1.Should().NotBeNull());
@@ -442,8 +442,8 @@ public void TupleCreation(Tuple<Foo, string> dummy)
             "And another type"
                 .See<string>();
 
-            "When I create a dummy value tuple of those types"
-                .x(() => dummy = A.Dummy<Tuple<Foo, string>>());
+            "When a dummy tuple of those types of these types is requested"
+                .x(() => dummy = this.CreateDummy<Tuple<Foo, string>>());
 
             "Then the first item of the tuple is a dummy"
                 .x(() => dummy.Item1.Should().BeOfType<Foo>());
@@ -461,8 +461,8 @@ public void ValueTupleCreation((Foo foo, string s) dummy)
             "And another type"
                 .See<string>();
 
-            "When I create a dummy value tuple of those types"
-                .x(() => dummy = A.Dummy<(Foo, string)>());
+            "When a dummy value tuple of those types is requested"
+                .x(() => dummy = this.CreateDummy<(Foo, string)>());
 
             "Then the first item of the tuple is a dummy"
                 .x(() => dummy.foo.Should().BeOfType<Foo>());