How to find individual words and their count?

[kartikthapar]

Consider the search pattern alpha which can be found in different ways like: alpha, alpha1, alpha2 or 1alpha, 2alpha and so on. I would like to run a search that gives me the following output:

Hit	Count
alpha	150
alpha1	100
1alpha	200

and so on.

What is the best way to accomplish this using ripgrep?

[BurntSushi]

For this very specific situation, this is what I would do:

$ cat corpus1
alpha alpha1 alpha2 1alpha 2alpha
alpha alpha1 alpha2 1alpha 2alpha
alpha alpha1 alpha2 1alpha 2alpha
alpha alpha1 alpha2 1alpha 2alpha
alpha alpha1 alpha2 1alpha 2alpha
alpha alpha1 alpha2 1alpha 2alpha

$ cat corpus2
alpha alpha1 alpha2 1alpha 2alpha
alpha alpha1 alpha2 1alpha 2alpha
alpha alpha1 alpha2 1alpha 2alpha
alpha alpha1 alpha2 1alpha 2alpha
alpha alpha1 alpha2 1alpha 2alpha
alpha alpha1 alpha2 1alpha 2alpha

$ for w in alpha alpha1 alpha2 1alpha 2alpha; do count="$(rg -w "$w" -o | wc -l)"; echo "$w\t$count"; done
alpha   12
alpha1  12
alpha2  12
1alpha  12
2alpha  12

I suspect what you're after is a way to run ripgrep once and get output similar to this. That is not possible. ripgrep does not have any way of reporting or acting upon which pattern matched.

You could do something like this too though. Kinda depends on the actual problem you're trying to solve:

$ rg -w '\d*alpha\d*' -o --no-filename | sort | uniq -c
     12 1alpha
     12 2alpha
     12 alpha
     12 alpha1
     12 alpha2