India - Water #36
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India - Water #36
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CheezItMan
reviewed
Nov 4, 2020
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| # Time complexity: O(n) | ||
| # Space complexity: O(n) | ||
| def factorial(n) |
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| # Time complexity: ? | ||
| # Space complexity: ? | ||
| def reverse(s) |
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| # Time complexity: O(n^2) | ||
| # Space complexity: O(n^2) | ||
| def reverse_inplace(s) |
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⚠ This method is not reversing the string in place, instead it's creating a new string with each recursive call.
Could you see a way to do it with the following method signature?
Suggested change
| # Time complexity: O(n^2) | |
| # Space complexity: O(n^2) | |
| def reverse_inplace(s) | |
| # Time complexity: O(n^2) | |
| # Space complexity: O(n^2) | |
| def reverse_inplace(s, low = 0, high = s.length - 1) |
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| # Time complexity: O(n) | ||
| # Space complexity: O(n) | ||
| def bunny(n) |
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| # Time complexity: O(n^2) | ||
| # Space complexity: O(n^2) | ||
| def search(array, value) |
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👍 However can you see how to do this method with O(n) space/time complexity?
| return false | ||
| else | ||
| return is_palindrome(s[1..-2]) | ||
| end | ||
| end | ||
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| # Time complexity: O(n^2) | ||
| # Space complexity: O(n^2) | ||
| def is_palindrome(s) |
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👍 Similar note to the above on time/space complexity.
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