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Cyndi #15
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Cyndi #15
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,64 @@ | ||
class TreeNode | ||
attr_accessor :value, :left, :right | ||
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def initialize(val) | ||
@value = val | ||
@left = nil | ||
@right = nil | ||
end | ||
end | ||
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class Tree | ||
attr_reader :root | ||
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def initialize | ||
@root = nil | ||
end | ||
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def add(value) | ||
new_node = TreeNode.new(value) | ||
if @root.nil? | ||
@root = new_node | ||
else | ||
add_helper(@root, new_node) | ||
end | ||
end | ||
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def add_helper(current, new_node) | ||
return new_node if current.nil? | ||
if new_node <= current.value | ||
current.left = add_helper(current.left, new_node) | ||
else | ||
current.right = add_helper(current.right, new_node) | ||
end | ||
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return current | ||
end | ||
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def inorder(current, array) | ||
if current == nil | ||
return | ||
else | ||
inorder(current.left, array) | ||
array << current.value | ||
inorder(current.right, array) | ||
end | ||
end | ||
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def loop_traverse(root) | ||
stack = [] | ||
output = [] | ||
current = root | ||
while (current || !stack.empty?) | ||
while (current) | ||
stack.push(current) | ||
current = current.left | ||
end | ||
current = stack.pop | ||
output.push(current.value); #storing the data | ||
current = current.right | ||
end | ||
puts "loop_traverse:" #prints out the output | ||
puts output.join(" ") | ||
end | ||
end |
Original file line number | Diff line number | Diff line change |
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@@ -2,61 +2,191 @@ class TreeNode | |
attr_reader :key, :value | ||
attr_accessor :left, :right | ||
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def initialize(key, val) | ||
def initialize(key, val) | ||
@key = key | ||
@value = val | ||
@left = nil | ||
@right = nil | ||
end | ||
end | ||
end | ||
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class Tree | ||
attr_reader :root | ||
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def initialize | ||
@root = nil | ||
end | ||
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# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: if balanced, O(log h) where h is the height of the tree | ||
# Space Complexity: if balanced, O(log h) where h is the height of the tree | ||
def add(key, value) | ||
raise NotImplementedError | ||
new_node = TreeNode.new(key, value) | ||
if @root.nil? | ||
@root = new_node | ||
else | ||
add_helper(@root, new_node) | ||
end | ||
end | ||
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def add_helper(current, new_node) | ||
if new_node.key <= current.key | ||
if current.left | ||
add_helper(current.left, new_node) | ||
else | ||
current.left = new_node | ||
end | ||
else | ||
if current.right | ||
add_helper(current.right, new_node) | ||
else | ||
current.right = new_node | ||
end | ||
end | ||
end | ||
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# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: O(h) if balanced, where h is the height of the tree | ||
# Space Complexity: O(1) | ||
def find(key) | ||
raise NotImplementedError | ||
return nil if @root.nil? | ||
current = @root | ||
while !current.nil? | ||
if key == current.key | ||
return current.value | ||
elsif key <= current.key | ||
current = current.left | ||
else | ||
current = current.right | ||
end | ||
end | ||
end | ||
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# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: O(n^2) where n is the number of nodes | ||
# Space Complexity: O(n) | ||
def inorder | ||
raise NotImplementedError | ||
stack = [] | ||
output = [] | ||
current = root | ||
while current || !stack.empty? | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. It's neat how you used stacks here to avoid the recursive solution. |
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while !current.nil? | ||
stack.push(current) | ||
current = current.left | ||
end | ||
current = stack.pop | ||
new_hash = Hash.new | ||
new_hash[:key] = current.key | ||
new_hash[:value] = current.value | ||
output.push(new_hash); #storing the data | ||
current = current.right | ||
end | ||
return output | ||
end | ||
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# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: if well balanced, O(h) where h is the height of the tree | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. You could also say O(log n) if it's balanced, except that since you're going to visit each node in the tree, it has to be O(n) |
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# Space Complexity: O(h) | ||
def preorder | ||
raise NotImplementedError | ||
stack = [] | ||
output = [] | ||
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current = @root | ||
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return [] if current.nil? | ||
stack.push(current) | ||
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while !stack.empty? | ||
current = stack.pop() | ||
new_hash = Hash.new | ||
new_hash[:key] = current.key | ||
new_hash[:value] = current.value | ||
output.push(new_hash) | ||
if current.right | ||
stack.push(current.right) | ||
end | ||
if current.left | ||
stack.push(current.left) | ||
end | ||
end | ||
return output | ||
end | ||
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# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: if balanced, O(h) where h is the height of the tree | ||
# Space Complexity: O(h) | ||
def postorder | ||
raise NotImplementedError | ||
stack = [] | ||
output = [] | ||
return [] if @root.nil? | ||
stack.push(@root) | ||
while !stack.empty? | ||
current = stack.pop() | ||
new_hash = Hash.new | ||
new_hash[:key] = current.key | ||
new_hash[:value] = current.value | ||
output.push(new_hash) | ||
if current.left | ||
stack.push(current.left) | ||
end | ||
if current.right | ||
stack.push(current.right) | ||
end | ||
end | ||
return output.reverse | ||
end | ||
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# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: if balanced, O(h) where h is the height of the tree | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Since you have to visit each node to figure out the height, it's O(n) for time complexity. Space is different. |
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# Space Complexity: O(h) | ||
def height | ||
raise NotImplementedError | ||
stack = [] | ||
current = @root | ||
stack.push(current) | ||
count_left = 0 | ||
count_right = 0 | ||
max_count = 0 | ||
while !stack.empty? | ||
current = stack.pop | ||
if current.left | ||
count_left += 1 | ||
stack.push(current.left) | ||
else | ||
if count_left > max_count | ||
max_count = count_left | ||
count_left = 0 | ||
end | ||
end | ||
if current.right | ||
count_right += 1 | ||
stack.push(current.right) | ||
else | ||
if count_right > max_count | ||
max_count = count_right | ||
count_right = 0 | ||
end | ||
end | ||
end | ||
return max_count | ||
end | ||
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# Optional Method | ||
# Time Complexity: | ||
# Space Complexity: | ||
# Time Complexity: if balanced, O(h) where h is the height of the tree | ||
# Space Complexity: O(h) | ||
def bfs | ||
raise NotImplementedError | ||
return [] if @root.nil? | ||
queue = [] | ||
output = [] | ||
queue.push(@root) | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Niiice! |
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while !queue.empty? | ||
current = queue[0] | ||
new_hash = Hash.new | ||
new_hash[:key] = current.key | ||
new_hash[:value] = current.value | ||
output.push(new_hash) | ||
if current.left | ||
queue.push(current.left) | ||
end | ||
if current.right | ||
queue.push(current.right) | ||
end | ||
queue = queue[1..-1] | ||
end | ||
return output | ||
end | ||
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# Useful for printing | ||
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What's this file for?