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函数的参数具有逆变性质 #10

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xiaochengzi6 opened this issue Feb 24, 2023 · 0 comments

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xiaochengzi6 commented Feb 24, 2023

函数的参数具有逆变性质，当参数为多类型时，就会触发参数的逆变性质将联合类型变成交叉类型

type UnionToIntersection<U> = 
    (U extends U ? (x: U) => unknown : never) extends (x: infer R) => unknown
        ? R
        : never;

type UnionToIntersectionResult = UnionToIntersection<{ guang: 1 } | { dong: 2 }>;

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