LC_Compare_Version_Numbers.py

"""
165. Compare Version Numbers

Compare two version numbers version1 and version2.
If version1 > version2 return 1; if version1 < version2 return -1;otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Example 1:

Input: version1 = "0.1", version2 = "1.1"
Output: -1
Example 2:

Input: version1 = "1.0.1", version2 = "1"
Output: 1
Example 3:

Input: version1 = "7.5.2.4", version2 = "7.5.3"
Output: -1
Seen this question in a real interview before?
"""

class Solution(object):
    def compareVersion(self, version1, version2):
        """
        :type version1: str
        :type version2: str
        :rtype: int
        """
        v1 = [ int(item) for item in version1.split(".")]
        v2 = [ int(item) for item in version2.split(".")]
        for i in range(max(len(v1),len(v2))):
            v1item = v1[i] if i < len(v1) else 0
            v2item = v2[i] if i < len(v2) else 0
            if (v1item > v2item):
                return 1
            elif (v1item < v2item):
                return -1
        return 0