ls: ignore leading period when sorting by name

[tertsdiepraam]

The GNU ls ignores the leading period when sorting by name. However, hidden files still get sorted before non-hidden files with the same name, so .a always appears before a.

Here is an example:

$ touch a b .a .b
$ ls -A            # GNU
.a  a  .b  b
$ uu-ls -A         # current uutils
.a  .b  a  b

Code is here:
https://github.com/uutils/coreutils/blob/master/src/uu/ls/src/ls.rs

Tests are here:
https://github.com/uutils/coreutils/blob/master/tests/by-util/test_ls.rs

[ricardoaiglesias]

Just verifying, all this would take is changing the sort_entries function's Sort::Size branch to split into two "buckets" (with dot and without dot), sort each bucket, and then join them, right?
If so, I can tackle this.

[tertsdiepraam]

@ricardoaiglesias If I understand you correctly I think that would lead to our current sorting right? In the example above, this would lead to a bucket with .a .b and a bucket with a b and joining them then gives .a .b a b.

One way this might be implemented is to sort by a tuple of type (String, bool) representing (name_without_leading_period, has_leading_period).

[ricardoaiglesias]

Oh sorry. I misinterpreted the examples you gave.
Yeah, you're correct. I can get something done.

[tertsdiepraam]

Nice! Looking forward to it!

[ricardoaiglesias]

PR Here: #2112

[ricardoaiglesias]

This issue can be closed.