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I found that the default result is the same as Python(scipy.interpolate.CubicSpline)'s natural boundary condition.
But I don't know how to match the default result of Python(with default boundary condition not-a-knot)
The text was updated successfully, but these errors were encountered:
I found that the default result is the same as Python(scipy.interpolate.CubicSpline)'s
natural
boundary condition.But I don't know how to match the default result of Python(with default boundary condition
not-a-knot
)The text was updated successfully, but these errors were encountered: