Is there any way to make route().current() also match params?

[mikemand]

Expected Behavior

Some way to determine that the route matches, including params. For example, if I'm on any of the following pages, route().current('backend.inventory.show') returns true because the route name is the same for all:

• /backend/inventory/1/category/2
• /backend/inventory/2/category/2
• /backend/inventory/3/category/13
• /backend/inventory/7/category/1
• /backend/inventory/1/category/13

Current Behavior

I'm not sure if there is already some method or argument to a method that will allow me to determine this.

For bug reports only please provide

Currently installed Laravel version:

5.8.15

Currently installed Ziggy version

0.7.1

Example route from your Laravel Routes file.

Route::get('/backend/inventory/{tenant}/category/{category}', [Backend\InventoryController::class, 'show'])->name('backend.inventory.show');

Contents of Ziggy.namedRoutes

"backend.inventory.show": {
	"domain": null,
	"methods": [
		"GET",
		"HEAD"
	],
	"uri": "backend/inventory/{tenant}/category/{category}"
}

Ziggy call in context

I have a custom Vue directive that uses the href attribute to determine if the link is to the current page. The link's href will be a route: <a :href="route('backend.inventory.show'. { tenant: currentTenant, category: category.id })">{{ category.name }}</a>

export default function (el, binding, vNode) {
    let { name } = vNode.data.attrs.href;

    if (name === undefined) {
        return;
    }

    // You can ignore this part, it works as intended for those routes that I DO want to be fuzzy matched.
    if (binding.modifiers.fuzzy) {
        const parts = name.split('.');

        if (parts.length > 1) {
            parts.splice(-1, 1, '*'); // remove last segment of route and replace with fuzzy token
            name = parts.join('.');
        }
    }

    if (route().current(name)) {
        el.classList.add('active');
    }
}

[DanielCoulbourne]

This is a good idea. I mayyyyy have time for it tomorrow, but I can't be sure and if not it will be a couple weeks.

[m1guelpf]

@DanielCoulbourne Sorry to bother you, but is there any progress on this? :D

[TheNewSound]

I would like to see that current() wont return a name but the whole route object, including resolved parameters

Example:
Route: /item/{name}
Current url: /item/example
So I could use current().parameters to get: {name: example}

[reinink]

I just ran into this myself. It would be awesome if Ziggy handled this out of the box! 👌

[bakerkretzmar]

@TheNewSound interesting idea, can you make a new issue for that feature specifically?

Just remembered this is already possible, it's route().params. See the tests for an example.

[bakerkretzmar]

This was added in #330 and will be available shortly in Ziggy 1.0 💪🏻

[mikemand]

That's so awesome! Thank you @bakerkretzmar. Also, hurray for 1.0 release!