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Copy path20. Valid Parentheses(Easy).js
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20. Valid Parentheses(Easy).js
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// 20. Valid Parentheses
/* Given a string s containing just the characters '(', ')', '{', '}', '[' and ']',
determine if the input string is valid.
// An input string is valid if:
// Open brackets must be closed by the same type of brackets.
// Open brackets must be closed in the correct order.
// Every close bracket has a corresponding open bracket of the same type.
Example 1:
Input: s = "()"
Output: true
Example 2:
Input: s = "()[]{}"
Output: true
Example 3:
Input: s = "(]"
Output: false
Example 4:
Input: s = "([])"
Output: true
*/
function _validParems(s) {
const stack = [];
const valid = "() {} []";
let i = 0;
while (i < s.length) {
stack.push(s[i]);
i++;
let open = stack[stack.length - 2];
let close = stack[stack.length - 1];
const temp = open + close;
if (valid.includes(temp)) {
stack.pop();
stack.pop();
}
}
return stack.length === 0;
}
//----------------------------------------- Or
const validParentheses = (s) => {
const stack = [];
const validMatches = {
")": "(",
"}": "{",
"]": "[",
};
for (let i = 0; i < s.length; i++) {
let char = s[i];
if (char === "(" || char === "{" || char === "[") {
stack.push(char);
} else if (char === "}" || char === "]" || char === ")") {
if (stack.length === 0 || stack.pop() !== validMatches[char]) {
return false;
}
}
}
return stack.length === 0;
};
//----------------------------------------- Or
function _validParentheses(s) {
const stack = [];
for (let i = 0; i < s.length; i++) {
let char = s[i];
if (char === "(" || char === "{" || char === "[") {
stack.push(char);
} else if (char === "}" && stack[stack.length - 1] === "{") {
stack.pop();
} else if (char === "]" && stack[stack.length - 1] === "[") {
stack.pop();
} else if (char === ")" && stack[stack.length - 1] === "(") {
stack.pop();
} else return false;
}
return stack.length === 0;
}
console.log(_validParens("(())"));