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Serialization.deserialize
Maybe
Serialization.deserialize(path::AbstractPath) = deserialize(IOBuffer(read(path)))
which would work for S3Paths. Similarly, serialize could be defined.
serialize
The text was updated successfully, but these errors were encountered:
Sure. Looks like deserialization for string filepaths was added in 1.1, so that would be consistent.
deserialization
deserialize(filename::AbstractString) Open a file and deserialize its contents. │ Julia 1.1 │ │ This method is available as of Julia 1.1.
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Maybe
which would work for S3Paths. Similarly,
serialize
could be defined.The text was updated successfully, but these errors were encountered: