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Language_Basics_Level_1.md

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Language Basics – Level 1

In this first part, we introduce the basic notions provided by Tom: the definition of a data-type, the construction of data (i.e. trees), and the transformation of such data using pattern-matching.

Defining a data-structure

One of the most simple Tom programs is the following. It defines a data-type to represent Peano integers and builds the integers 0=zero and 1=suc(zero):

import main.peano.types.*;
  public class Main {
  %gom {
    module Peano
    abstract syntax
    Nat = zero()
        | suc(pred:Nat)
        | plus(x1:Nat, x2:Nat)
  }
  public final static void main(String[] args) {
    Nat z   = `zero();
    Nat one = `suc(z);
    System.out.println(z);
    System.out.println(one);
  }
}

The %gom {...} construct defines a data-structure, also called signature or algebraic data-type. This data-structure declares a sort (Nat) that has three operators (zero, suc, and plus). These operators are called constructors, because they are used to construct the data-structure. zero is a constant (arity 0), whereas the arities of suc and plus are respectively 1 and 2. Note that a name has to be given for each slot (pred for suc, and x1, x2 for plus).

Retrieving information in a data-structure

In addition to %gom and `, Tom provides a third construct: %match. Using the same program, we add a method evaluate(Nat n) and we modify the method run():

import main.peano.types.*;
  public class Main {
  %gom {
    module Peano
    abstract syntax
    Nat = zero()
        | suc(pred:Nat)
        | plus(x1:Nat, x2:Nat)
  }
  public final static void main(String[] args) {
    Nat two = `plus(suc(zero()),suc(zero()));
    System.out.println(two);
    two = evaluate(two);
    System.out.println(two);
  }
  public static Nat evaluate(Nat n) {
    %match(n) {
      plus(x, zero()) -> { return `x; }
      plus(x, suc(y)) -> { return `suc(plus(x,y)); }
    }
    return n;
  }
}

The %match construct is similar to switch/case in the sense that given a tree (n), the %match selects the first pattern that matches the tree, and executes the associated action. By matching, we mean: giving values to variables to make the pattern equal to the subject. In our example n has the value plus(suc(zero()),suc(zero())). The first pattern does not match n, because the second subterm of n is not a zero(), but a suc(zero()). In this example, the second pattern matches n and gives the value suc(zero()) to x, and zero() to y.

When a pattern matches a subject, we say that the variables (x and y in our case) are instantiated. They can then be used in the action part (also called right-hand side). Similarly, the second rules can be applied when the second subterm is rooted by a suc. In that case, x and y are instantiated.

The method evaluate defines the addition of two integers represented by Peano successors (i.e. zero and suc). The first case says that the addition of an integer with zero is evaluated into the integer itself. The second case builds a new term (rooted by suc) whose subterm (plus(x,y)) denotes the addition of x and y.

When executing the program we obtain:

plus(suc(zero()),suc(zero()))
suc(plus(suc(zero()),zero()))

Using rules to simplify expressions

In this section, we will show how to use the notion of rules to simplify expressions. Suppose that we want to simplify boolean expressions. It is frequent to define the relations between expressions using a set of simplification rules like the following:

Not(a)				→	Nand(a,a)
Or(a, b)			→	Nand(Not(a), Not(b))
And(a, b)			→	Not(Nand(a, b))
Xor(a, b)			→	Or(And(a, Not(b)), And(Not(a), b))
Nand(False, b)		→	True
Nand(a, False)		→	True
Nand(True, True)	→	False

To encode such a simplification system, we have to implement a function that simplifies an expression until no more reduction can be performed. This can of course be done using functions defined in Java, combined with the %match constructs, but it is more convenient to use an algebraic construct that ensures that a rule is applied whenever a reduction is possible. For this purpose, the %gom construct provides a rule() construct where the left and the right-hand sides are terms. The previous simplification system can be defined as follows:

import gates.logic.types.*;
  public class Gates {
    %gom {
      module Logic
        imports int
        abstract syntax
        Bool = Input(n:int)
             | True()
             | False()
             | Not(b:Bool)
             | Or(b1:Bool, b2:Bool)
             | And(b1:Bool, b2:Bool)
             | Nand(b1:Bool, b2:Bool)
             | Xor(b1:Bool, b2:Bool)

        module Logic:rules() {
          Not(a)   -> Nand(a,a)
          Or(a,b)  -> Nand(Not(a),Not(b))
          And(a,b) -> Not(Nand(a,b))
          Xor(a,b) -> Or(And(a,Not(b)),And(Not(a),b))
          Nand(False(),_)     -> True()
          Nand(_,False())     -> True()
          Nand(True(),True()) -> False()
        }
    }
    public final static void main(String[] args) {
    Bool b = `Xor(True(),False());
    System.out.println("b = " + b);
  }
}

When using the module Logic:rules() { ... } constructs, the simplification rules are integrated into the data-structure. This means that the rules are applied any time it is possible to do a reduction. The user does not have any control on them, and thus cannot prevent from applying a rule. Of course, the simplification system should be terminating, otherwise, infinite reductions may occur. When compiling and executing the previous program, we obtain b = True().

Separating Gom from Tom (*)

When programming large applications, it may be more convenient to introduce several classes that share a common data-structure. In that case, the %gom {...} construct could be avoided and a Gom file (Logic.gom for example) could be used instead:

module Logic
imports int
abstract syntax
Bool = Input(n:int)
     | True()
     | False()
     | Not(b:Bool)
     | Or(b1:Bool, b2:Bool)
     | And(b1:Bool, b2:Bool)
     | Nand(b1:Bool, b2:Bool)
     | Xor(b1:Bool, b2:Bool)

module Logic:rules() {
  Not(a)   -> Nand(a,a)
  Or(a,b)  -> Nand(Not(a),Not(b))
  And(a,b) -> Not(Nand(a,b))
  Xor(a,b) -> Or(And(a,Not(b)),And(Not(a),b))
  Nand(False(),_)     -> True()
  Nand(_,False())     -> True()
  Nand(True(),True()) -> False()
}

This file can by compiled as follows:

$ gom Logic.gom

This generates several Java classes, among them a particular file called Logic.tom which explains to Tom how the data-structure is implemented. This process is hidden when using the %gom {...} construct:

$ ls logic
_Logic.tom              Logic.tom               LogicAbstractType.java
strategy                types

One of the simplest Tom program that uses the defined data-structure is the following:

import logic.types.*;
public class Main {
  %include{ logic/Logic.tom }
  public final static void main(String[] args) {
    Bool b = `Xor(True(),False());
    System.out.println("b = " + b);
  }
}

Programming in Tom

In this section we present how Tom can be used to describe the abstract syntax and to implement an interpreter for a given language. We also give some tips and more information about the generated code.

When using %gom { ... }, the generated data-structure is particular: data are maximally shared. This technique, also known as hash-consing ensures that two identical subterms are implemented by the same objects. Therefore, the memory footprint is minimal and the equality-check can be done in constant time using the == construct (two terms are identical if the pointers are equal). As a consequence, a term is not mutable: once created, it cannot be modified.

Even if the generated API offers getters and setters for each defined slot (Bool getb1(), Bool getb2(), Bool setb1(Bool t) and Bool setb2(Bool t) for the And(b1:Bool,b2:Bool) defined below). These methods do not really modify the term on which they are applied: t.setb1(‘True()) will return a copy of t where the first child is set to True(), but the previous t is not modified. There is no side-effect in a maximally shared setting.

In Tom, it is quite easy to quickly develop applications which manipulates trees. As an example, let us consider a tiny language composed of boolean expressions (True, False, And, Or, and Not), expressions (constant, variable, Plus, Mult, and Mod), and instructions (Skip, Print, ;, If, and While). The abstract syntax of this language can be described as follows:

import pico1.term.types.*;
import java.util.*;
  class Pico1 {
    %gom {
      module Term
      imports int String
      abstract syntax
      Bool = True()
           | False()
           | Not(b:Bool)
           | Or(b1:Bool, b2:Bool)
           | And(b1:Bool, b2:Bool)
           | Eq(e1:Expr, e2:Expr)
      Expr = Var(name:String)
           | Cst(val:int)
           | Plus(e1:Expr, e2:Expr)
           | Mult(e1:Expr, e2:Expr)
           | Mod(e1:Expr, e2:Expr)
      Inst = Skip()
           | Assign(name:String, e:Expr)
           | Seq(i1:Inst, i2:Inst)
           | If(cond:Bool, i1:Inst, i2:Inst)
           | While(cond:Bool, i:Inst)
           | Print(e:Expr)
    }
  ...
}

Assume that we want to write an interpreter for this language, we need a notion of environment to store the value assigned to a variable. A simple solution is to use a Map which associate an expression (of sort Expr) to a name of variable (of sort String). Given this environment, the evaluation of an expression can be implemented as follows:

public static Expr evalExpr(Map env,Expr expr) {
  %match(expr) {
    Var(n)                -> { return (Expr)env.get(`n); }
    Plus(Cst(v1),Cst(v2)) -> { return `Cst(v1 + v2); }
    Mult(Cst(v1),Cst(v2)) -> { return `Cst(v1 * v2); }
    Mod(Cst(v1),Cst(v2))  -> { return `Cst(v1 % v2); }
    // congruence rules
    Plus(e1,e2) -> { return `evalExpr(env,Plus(evalExpr(env,e1),evalExpr(env,e2))); }
    Mult(e1,e2) -> { return `evalExpr(env,Mult(evalExpr(env,e1),evalExpr(env,e2))); }
    Mod(e1,e2)  -> { return `evalExpr(env,Mod(evalExpr(env,e1),evalExpr(env,e2)));  }
    x -> { return `x; }
  }
  throw new RuntimeException("should not be there: " + expr);
}

Similarly, the evaluation of boolean expressions can be implemented as follows:

public static Bool evalBool(Map env,Bool bool) {
  %match(bool) {
    Not(True())     -> { return `False(); }
    Not(False())    -> { return `True(); }
    Not(b)          -> { return `evalBool(env,Not(evalBool(env,b))); }
    Or(True(),_)    -> { return `True(); }
    Or(_,True())    -> { return `True(); }
    Or(False(),b2)  -> { return `evalBool(env, b2); }
    Or(b1,False())  -> { return `evalBool(env, b1); }
    Or(b1,b2)       -> { return `evalBool(env, Or(evalBool(env,b1),evalBool(env,b2))); }
    And(True(),b2)  -> { return `evalBool(env, b2); }
    And(b1,True())  -> { return `evalBool(env, b1); }
    And(False(),_)  -> { return `False(); }
    And(_,False())  -> { return `False(); }
    And(b1,b2)      -> { return `evalBool(env, And(evalBool(env,b1),evalBool(env,b2))); }
    Eq(e1,e2)       -> {
      Expr x = `evalExpr(env,e1);
      Expr y = `evalExpr(env,e2);
      return (x==y)?`True():`False();
    }
    x               -> { return `x; }
  }
  throw new RuntimeException("should not be there: " + bool);
}

Once defined the methods evalExpr and evalBool, it becomes easy to define the interpreter:

public static void eval(Map env, Inst inst) {
  %match(inst) {
    Skip() -> {
      return;
    }
    Assign(name,e) -> {
      env.put(`name,evalExpr(env,`e));
      return;
    }
    Seq(i1,i2) -> {
      eval(env,`i1);
      eval(env,`i2);
      return;
    }
    Print(e) -> {
      System.out.println(evalExpr(env,`e));
      return;
    }
    If(b,i1,i2) -> {
      if(evalBool(env,`b)==`True()) {
        eval(env,`i1);
      } else {
        eval(env,`i2);
      }
      return;
    }
    w@While(b,i) -> {
      Bool cond = evalBool(env,`b);
      if(cond==`True()) {
        eval(env,`i);
        eval(env,`w);
      }
      return;
    }
  }
  throw new RuntimeException("strange term: " + inst);
}

To play with the Pico language, we just have to initialize the environment (env), create programs (p1 and p2), and evaluate them (eval):

public final static void main(String[] args) {
  Map env = new HashMap();
  Inst p1 = `Seq(Assign("a",Cst(1)) , Print(Var("a")));
  System.out.println("p1: " + p1);
  eval(env,p1);
  Inst p2 = `Seq(Assign("i",Cst(0)),
               While(Not(Eq(Var("i"),Cst(10))),
                     Seq(Print(Var("i")),
                         Assign("i",Plus(Var("i"),Cst(1))))));
  System.out.println("p2: " + p2);
  eval(env,p2);
}

Exercise: write a Pico program that computes prime numbers up to 100.