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move-element-to-end.py
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# Move Element To End
# 🟠 Medium
#
# https://www.algoexpert.io/questions/move-element-to-end
#
# Tags: Array - Two Pointers
import timeit
# Use a read and an insert pointers, first make sure that the value
# under the insert pointer is not the target value, then check the read
# pointer and, if it holds the target value, swap them and slide both
# pointers.
#
# Time complexity: O(n) - We will visit each element once.
# Space complexity: O(1) - Constant extra memory.
class Solution:
def moveElementToEnd(self, array, toMove):
# Use two pointers, read and insert.
read, insert = 0, len(array) - 1
while read < insert:
# If the value under the insert pointer is the
# target, we don't want to insert there.
if array[insert] == toMove:
insert -= 1
continue
# Insert now points to a different value.
# If read points to the target value, swap it with insert.
if array[read] == toMove:
array[read], array[insert] = array[insert], array[read]
insert -= 1
# Always slide the read pointer.
read += 1
return array
def test():
executors = [Solution]
tests = [
[[], 8, []],
[[3, 3, 3, 3, 3], 3, [3, 3, 3, 3, 3]],
[[3, 1, 2, 4, 5], 3, [5, 1, 2, 4, 3]],
[[2, 1, 2, 2, 2, 3, 4, 2], 2, [4, 1, 3, 2, 2, 2, 2, 2]],
]
for executor in executors:
start = timeit.default_timer()
for _ in range(1):
for col, t in enumerate(tests):
sol = executor()
result = sol.moveElementToEnd(t[0], t[1])
exp = t[2]
assert result == exp, (
f"\033[93m» {result} <> {exp}\033[91m for"
+ f" test {col} using \033[1m{executor.__name__}"
)
stop = timeit.default_timer()
used = str(round(stop - start, 5))
cols = "{0:20}{1:10}{2:10}"
res = cols.format(executor.__name__, used, "seconds")
print(f"\033[92m» {res}\033[0m")
test()