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When the pointer isn't wrapped in a Pin, its address may be changed, which can e.g. change the ByAddress's hash while leaving it in the wrong bucket of a HashMap. The only way to prevent this is to have ByAddress<T> wrap a Pin<T>.
The text was updated successfully, but these errors were encountered:
When the pointer isn't wrapped in a Pin, its address may be changed, which can e.g. change the ByAddress's hash while leaving it in the wrong bucket of a HashMap. The only way to prevent this is to have
ByAddress<T>
wrap aPin<T>
.The text was updated successfully, but these errors were encountered: