Question 5.ipynb

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    "## Asignment 1"
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   "source": [
    "### Question 5"
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   "source": [
    "#### Consider the vector 1:K, where K is a positive integer. \n",
    "#### Write an R command that determines how many elements in the vector are exactly divisible by 3."
   ]
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    "K = 16\n",
    "vect = 1:K"
   ]
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       "<ol class=list-inline>\n",
       "\t<li>1</li>\n",
       "\t<li>2</li>\n",
       "\t<li>3</li>\n",
       "\t<li>4</li>\n",
       "\t<li>5</li>\n",
       "\t<li>6</li>\n",
       "\t<li>7</li>\n",
       "\t<li>8</li>\n",
       "\t<li>9</li>\n",
       "\t<li>10</li>\n",
       "\t<li>11</li>\n",
       "\t<li>12</li>\n",
       "\t<li>13</li>\n",
       "\t<li>14</li>\n",
       "\t<li>15</li>\n",
       "\t<li>16</li>\n",
       "</ol>\n"
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       "\\begin{enumerate*}\n",
       "\\item 1\n",
       "\\item 2\n",
       "\\item 3\n",
       "\\item 4\n",
       "\\item 5\n",
       "\\item 6\n",
       "\\item 7\n",
       "\\item 8\n",
       "\\item 9\n",
       "\\item 10\n",
       "\\item 11\n",
       "\\item 12\n",
       "\\item 13\n",
       "\\item 14\n",
       "\\item 15\n",
       "\\item 16\n",
       "\\end{enumerate*}\n"
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      "text/markdown": [
       "1. 1\n",
       "2. 2\n",
       "3. 3\n",
       "4. 4\n",
       "5. 5\n",
       "6. 6\n",
       "7. 7\n",
       "8. 8\n",
       "9. 9\n",
       "10. 10\n",
       "11. 11\n",
       "12. 12\n",
       "13. 13\n",
       "14. 14\n",
       "15. 15\n",
       "16. 16\n",
       "\n",
       "\n"
      ],
      "text/plain": [
       " [1]  1  2  3  4  5  6  7  8  9 10 11 12 13 14 15 16"
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   "source": [
    "vect"
   ]
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      "text/html": [
       "<ol class=list-inline>\n",
       "\t<li>3</li>\n",
       "\t<li>6</li>\n",
       "\t<li>9</li>\n",
       "\t<li>12</li>\n",
       "\t<li>15</li>\n",
       "</ol>\n"
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       "\\begin{enumerate*}\n",
       "\\item 3\n",
       "\\item 6\n",
       "\\item 9\n",
       "\\item 12\n",
       "\\item 15\n",
       "\\end{enumerate*}\n"
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      "text/markdown": [
       "1. 3\n",
       "2. 6\n",
       "3. 9\n",
       "4. 12\n",
       "5. 15\n",
       "\n",
       "\n"
      ],
      "text/plain": [
       "[1]  3  6  9 12 15"
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   "source": [
    "# Vector containing Elements Divisible by 3\n",
    "\n",
    "vect[vect %% 3 == 0]"
   ]
  },
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   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/html": [
       "5"
      ],
      "text/latex": [
       "5"
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      "text/markdown": [
       "5"
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      "text/plain": [
       "[1] 5"
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   "source": [
    "# Number of Elements Divisible by 3\n",
    "\n",
    "length(vect[vect %% 3 == 0])"
   ]
  }
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