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lab_sets.rkt
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lab_sets.rkt
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#lang eopl
;;-------------------------------------------------------------------------------
;; Name: Jacob Gerega
;; Pledge: I pledge my honor that I have abided by the Stevens Honor System.
;;-------------------------------------------------------------------------------
;; In this lab, you'll write some basic functions which operate on sets.
;; Scheme doesn't have a built-in "set" datatype,
;; so we'll use the list datatype as a stand-in for sets.
;; We'll make sure these lists don't contain duplicates,
;; and we won't care about the order of elements in the lists,
;; so for all intents and purposes they'll be sets!
;; So, in this lab, we can treat sets as lists,
;; but we can't treat regular lists as sets.
;; Here's a helper function which converts a list
;; to a set by removing duplicate elements.
;; It'll be useful for the subsequent functions you implement.
;; Type signature: (make-set list) -> set
(define (make-set L)
(cond [(null? L) '()]
[(member (car L) (cdr L)) (make-set (cdr L))]
[else (cons (car L) (make-set (cdr L)))]))
;;_______________________________________________________________________________
;; As you complete the following functions,
;; see if you can utilize them in the subsequent ones!
;; Take particular note of the inputs and outputs of each function
;; to confirm whether the expected types are lists or sets.
;; For all of the functions whose outputs are sets,
;; your outputs will be considered correct if they contain the correct elements,
;; regardless of their order.
;; Define element?
;; Given an item e and a list of items L,
;; returns #t if e is in L, #f otherwise.
;; Hint: to compare equality of any object type, use "equal?".
;; Examples:
;; (element? 0 '()) => #f
;; (element? 8 '(7 8 9)) => #t
;; (element? 7 '(1 2 3 4)) => #f
;; (element? 'saw '(the man saw a dog)) => #t
;; (element? 'sa '(the man saw a dog)) => #f
;; Type signature: (element? item list) -> boolean
(define (element? e L)
(if (eq? L '()) (eq? e '()) (if (eq? e (car L)) (eq? e (car L)) (element? e (cdr L)))))
;; Define union
;; Given two lists, returns a set containing all of the elements from either list.
;; Remember: for the functions that return a set,
;; the order of the elements in the output doesn't need to exactly match the examples.
;; Examples:
;; (union '(1 2 3) '(4 5 6)) => '(1 2 3 4 5 6)
;; (union '(1 2 3) '(0 1 2 3)) => '(0 1 2 3)
;; (union '(1 1 1) '()) => '(1)
;; Type signature: (union list list) -> set
(define (union LA LB)
(make-set (append LA LB)))
;; Define intersection
;; Given two lists A and B, returns the set
;; containing all elements in both A and B.
;; Examples:
;; (intersection '(1 2 3 4) '(2 4 5)) => '(2 4)
;; (intersection '(s a n d e e p) '(b h a t t)) => '(a)
;; (intersection '(c c c) '(c a c)) => '(c)
;; (intersection '(a a a) '()) => '()
;; Type signature: (intersection list list) -> set
(define (intersection LA LB)
(if (null? LA)
'()
(if(element? (car LA) LB)
(cons (car (make-set LA)) (intersection (cdr (make-set LA)) (make-set LB)))
(intersection (cdr LA) LB)
)
)
)
;; Define subset?
;; Given two sets A and B, returns whether A is a subset of B
;; (every element in A is also in B).
;; Examples:
;; (subset? '() '()) => #t
;; (subset? '(1 2 3) '(1 4 2 5 3)) => #t
;; (subset? '(115 284 385) '(115 146 284 135 385 392)) => #t
;; (subset? '(-2 0 2) '(-1 1 3)) => #f
;; (subset? '(-1 1 2) '(-1 1 3 5 7)) => #f
;; (subset? '(1 3 2) '(3 2 1)) => #t
;; Type signature: (subset? set set) -> boolean
(define (subset? SA SB)
(if (null? SA)
#t
(if (element? (car SA) SB)
(subset? (cdr SA) SB)
#f))
)
;; Define set-equal?
;; Given two sets A and B, returns whether A = B
;; (i.e. every element in A is in B and every element in B is in A).
;; NOTE: Since the order of elements in the sets may be different,
;; you can't simply use (equal? A B).
;; Examples:
;; (set-equal? '() '()) => #t
;; (set-equal? '(a b c) '(a b c)) => #t
;; (set-equal? '(a b c) '(a b c)) => #t
;; (set-equal? '(1 2 3) '(1 2 4)) => #f
;; (set-equal? '(5 5 5 5) '(5)) => #t
;; Type signature: (set-equal? set set) -> boolean
(define (set-equal? SA SB)
(if (and (null? SA) (null? SB))
#t
(if (not (eq? (length (make-set SA)) (length (make-set SB))))
#f
(if (element? (car (make-set SA)) (make-set SB))
(subset? (cdr (make-set SA)) (make-set SB))
#f
)
))
)
;; Define set-difference
;; Given lists A and B, returns the set of A - B
;; (i.e. every element in A which is not in B).
;; Examples:
;; (set-difference '(1 2 3) '(2 3 4)) => '(1)
;; (set-difference '(1 2 3) '(1 2 3)) => '()
;; (set-difference '(1 2 3) '(4 5 6)) => '(1 2 3)
;; (set-difference '() '(1 2 3)) => '()
;; (set-difference '(1 1 2 3 3) '()) => '(1 2 3)
;; Type signature: (set-difference list list) -> set
(define (set-difference LA LB)
(if (null? LA)
'()
(if (element? (car (make-set LA)) (make-set LB))
(set-difference (cdr (make-set LA)) (make-set LB))
(cons (car (make-set LA)) (set-difference (cdr (make-set LA)) (make-set LB)))
)
)
)
;; Define sym-diff
;; Given two lists A and B, returns the symmetric difference of A and B as sets,
;; which equals the union of A - B and B - A (i.e. every element in exactly one of the lists).
;; Examples:
;; (sym-diff '(1 2 3) '(3 4 5)) => '(1 2 4 5)
;; (sym-diff '(1 2 3) '(4 5 6)) => '(1 2 3 4 5 6)
;; (sym-diff '(1 2 3) '(1 2 3)) => '()
;; (sym-diff '(1 2) '(1 2 3 4)) => '(3 4)
;; (sym-diff '(1 1 1) '()) => '(1)
;; Type signature: (sym-diff list list) -> set
(define (sym-diff LA LB)
(union (set-difference LA LB) (set-difference LB LA)))
;; Define cardinality
;; Given a list L, returns |L|,
;; the number of unique elements in L.
;; Examples:
;; (cardinality '(1 2 3)) => 3
;; (cardinality '(1 1 2 3 3)) => 3
;; (cardinality '(5 5 5 5 5)) => 1
;; (cardinality '()) => 0
;; Type signature: (cardinality list) -> int
(define (cardinality L)
(length (make-set L)))
;; Define disjoint
;; Given two sets, returns if the sets are disjoint
;; (i.e. they have no elements in common).
;; Examples:
;; (disjoint? '(1 2 3) '()) => #t
;; (disjoint? '(1 2 3) '(1)) => #f
;; (disjoint? '(1 2 3) '(4 5 6)) => #t
;; Type signature: (disjoint? set set) -> boolean
(define (disjoint? SA SB)
(if (or (null? SB) (null? SA))
#t
(if (element? (car (make-set SA)) (make-set SB))
#f
(disjoint? (cdr (make-set SA)) (make-set SB)))
)
)
;; Define superset?
;; Given sets A and B, returns whether A is a superset of B
;; (i.e. every element in B is in A).
;; Examples:
;; (superset? '() '()) => #t
;; (superset? '(1 2 3 4 5) '(1 2 3)) => #t
;; (superset? '(-1 1 3) '(-2 0 2)) => #f
;; Type signature: (superset? set set) -> boolean
(define (superset? SA SB)
(if (null? SB)
#t
(if (element? (car (make-set SB)) (make-set SA))
(superset? (make-set SA) (cdr (make-set SB)))
#f)
)
)
;; Define insert
;; Given a list L and an item e,
;; returns the set of L with e added to the set.
;; Remember, if the new element was already in the set,
;; the resultant set does not change.
;; Examples:
;; (insert 0 '(1 2 3)) => '(0 1 2 3)
;; (insert 1 '(1 2 3)) => '(1 2 3)
;; (insert 0 '(0 0 0)) => '(0)
;; Type signature: (insert element list) -> set
(define (insert e L)
(make-set (cons e L)))
;; Define remove
;; Given a set S and an item e,
;; returns S with e removed from it.
;; If e was not in S to begin with,
;; the function should return S unchanged.
;; (remove 2 '(1 2 3)) => '(1 3)
;; (remove 3 '(3)) => '()
;; (remove 4 '(1 2 3)) => '(1 2 3)
;; Type signature: (remove element set) -> set
(define (remove e S)
(if (null? S)
'()
(if (eq? (car S) e)
(remove e (cdr S))
(cons (car S) (remove e (cdr S)))
)
)
)
;; Created January 2018 by Samuel Kraus and Edward Minnix
;; Updated February 2020 by Jared Pincus