Path.open() signature differs from pathlib, open() builtin

[barneygale]

If I call zipp.Path.open('r', 1), the last argument is interpreted as an encoding argument, whereas in pathlib.Path.open('r', 1) and open('foo', 'r', 1) the last argument is interpreted as a buffering argument.

Could the signature be adjusted to match pathlib and io? Thank you