how can i define SENTRY_RELEASE custom

[philos3]

release use name@version from pubspec (string) as default value, but how can i define SENTRY_RELEASE custom ， such as testflight@6.9.2+692 for ios app building, or googlplay@6.9.2+692 for android app building, or some channel as official@6.9.2+692

as i know ，i can edict yaml manually when building APP for each channel. but I want to know is there any more convenient way to do this

version: 6.9.2+692
SENTRY_RELEASE_IOS: testflight@6.9.2+692
SENTRY_RELEASE_IOS2: appstore@6.9.2+692
SENTRY_RELEASE: googlplay@6.9.2+692
SENTRY_RELEASE: official@6.9.2+692

[philos3]

It is convenient to define in code,but using sentry-dart-plugin how can i do this in yaml

options.release =
'${DataUtils.getMarketString()}@${Application.instance.appVersion}+${Application.instance.appBuildNum}';

[marandaneto]

You probably need this #81
So you can call the plugin and pass the values as parameters
eg dart run sentry_dart_plugin --dart-define=release=testflight@6.9.2+692 but we've not implemented this yet.
Your option is editing the YAML directly or setting the env. var. as an alternative.

You can also do if conditions and set the options.release dynamically depending on if its Android, or iOS.
Closing this in favor of #81

[eb-so]

Your option is editing the YAML directly or setting the env. var. as an alternative.

@marandaneto In my codemagic pipeline I'm increasing the build number automatically so I need the value of the release to match, Do the above solutions work in my case, if so please explain a bit about how to achieve them

[marandaneto]

@eb-so I'm no longer part of the Sentry staff. cc @buenaflor