From a666fc6fa96a4ae7a24a5830b3ec85e0c48a3aee Mon Sep 17 00:00:00 2001
From: Brandon Dail <brandon.dail@formidable.com>
Date: Tue, 28 Nov 2017 23:39:38 -0800
Subject: [PATCH] Remove findCurrentFiberUsingSlowPath.js

---
 .../src/findCurrentFiberUsingSlowPath.js      | 104 ------------------
 1 file changed, 104 deletions(-)
 delete mode 100644 packages/enzyme-adapter-react-16/src/findCurrentFiberUsingSlowPath.js

diff --git a/packages/enzyme-adapter-react-16/src/findCurrentFiberUsingSlowPath.js b/packages/enzyme-adapter-react-16/src/findCurrentFiberUsingSlowPath.js
deleted file mode 100644
index 916320ab8..000000000
--- a/packages/enzyme-adapter-react-16/src/findCurrentFiberUsingSlowPath.js
+++ /dev/null
@@ -1,104 +0,0 @@
-// Extracted from https://github.com/facebook/react/blob/7bdf93b17a35a5d8fcf0ceae0bf48ed5e6b16688/src/renderers/shared/fiber/ReactFiberTreeReflection.js#L104-L228
-function findCurrentFiberUsingSlowPath(fiber) {
-  const { alternate } = fiber;
-  if (!alternate) {
-    return fiber;
-  }
-  // If we have two possible branches, we'll walk backwards up to the root
-  // to see what path the root points to. On the way we may hit one of the
-  // special cases and we'll deal with them.
-  let a = fiber;
-  let b = alternate;
-  while (true) { // eslint-disable-line
-    const parentA = a.return;
-    const parentB = parentA ? parentA.alternate : null;
-    if (!parentA || !parentB) {
-      // We're at the root.
-      break;
-    }
-
-    // If both copies of the parent fiber point to the same child, we can
-    // assume that the child is current. This happens when we bailout on low
-    // priority: the bailed out fiber's child reuses the current child.
-    if (parentA.child === parentB.child) {
-      let { child } = parentA;
-      while (child) {
-        if (child === a) {
-          // We've determined that A is the current branch.
-          return fiber;
-        }
-        if (child === b) {
-          // We've determined that B is the current branch.
-          return alternate;
-        }
-        child = child.sibling;
-      }
-      // We should never have an alternate for any mounting node. So the only
-      // way this could possibly happen is if this was unmounted, if at all.
-      throw new Error('Unable to find node on an unmounted component.');
-    }
-
-    if (a.return !== b.return) {
-      // The return pointer of A and the return pointer of B point to different
-      // fibers. We assume that return pointers never criss-cross, so A must
-      // belong to the child set of A.return, and B must belong to the child
-      // set of B.return.
-      a = parentA;
-      b = parentB;
-    } else {
-      // The return pointers point to the same fiber. We'll have to use the
-      // default, slow path: scan the child sets of each parent alternate to see
-      // which child belongs to which set.
-      //
-      // Search parent A's child set
-      let didFindChild = false;
-      let { child } = parentA;
-      while (child) {
-        if (child === a) {
-          didFindChild = true;
-          a = parentA;
-          b = parentB;
-          break;
-        }
-        if (child === b) {
-          didFindChild = true;
-          b = parentA;
-          a = parentB;
-          break;
-        }
-        child = child.sibling;
-      }
-      if (!didFindChild) {
-        // Search parent B's child set
-        ({ child } = parentB);
-        while (child) {
-          if (child === a) {
-            didFindChild = true;
-            a = parentB;
-            b = parentA;
-            break;
-          }
-          if (child === b) {
-            didFindChild = true;
-            b = parentB;
-            a = parentA;
-            break;
-          }
-          child = child.sibling;
-        }
-        if (!didFindChild) {
-          throw new Error('Child was not found in either parent set. This indicates a bug ' +
-            'in React related to the return pointer. Please file an issue.');
-        }
-      }
-    }
-  }
-  if (a.stateNode.current === a) {
-    // We've determined that A is the current branch.
-    return fiber;
-  }
-  // Otherwise B has to be current branch.
-  return alternate;
-}
-
-module.exports = findCurrentFiberUsingSlowPath;