-
Notifications
You must be signed in to change notification settings - Fork 55
/
Assignment+2.py
198 lines (137 loc) · 7.04 KB
/
Assignment+2.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
# coding: utf-8
# ---
#
# _You are currently looking at **version 1.2** of this notebook. To download notebooks and datafiles, as well as get help on Jupyter notebooks in the Coursera platform, visit the [Jupyter Notebook FAQ](https://www.coursera.org/learn/python-data-analysis/resources/0dhYG) course resource._
#
# ---
# # Assignment 2 - Pandas Introduction
# All questions are weighted the same in this assignment.
# ## Part 1
# The following code loads the olympics dataset (olympics.csv), which was derrived from the Wikipedia entry on [All Time Olympic Games Medals](https://en.wikipedia.org/wiki/All-time_Olympic_Games_medal_table), and does some basic data cleaning.
#
# The columns are organized as # of Summer games, Summer medals, # of Winter games, Winter medals, total # number of games, total # of medals. Use this dataset to answer the questions below.
# In[1]:
import pandas as pd
df = pd.read_csv('olympics.csv', index_col=0, skiprows=1)
for col in df.columns:
if col[:2]=='01':
df.rename(columns={col:'Gold'+col[4:]}, inplace=True)
if col[:2]=='02':
df.rename(columns={col:'Silver'+col[4:]}, inplace=True)
if col[:2]=='03':
df.rename(columns={col:'Bronze'+col[4:]}, inplace=True)
if col[:1]=='№':
df.rename(columns={col:'#'+col[1:]}, inplace=True)
names_ids = df.index.str.split('\s\(') # split the index by '('
df.index = names_ids.str[0] # the [0] element is the country name (new index)
df['ID'] = names_ids.str[1].str[:3] # the [1] element is the abbreviation or ID (take first 3 characters from that)
df = df.drop('Totals')
df.head()
# ### Question 0 (Example)
#
# What is the first country in df?
#
# *This function should return a Series.*
# In[2]:
# You should write your whole answer within the function provided. The autograder will call
# this function and compare the return value against the correct solution value
def answer_zero():
# This function returns the row for Afghanistan, which is a Series object. The assignment
# question description will tell you the general format the autograder is expecting
return df.iloc[0]
# You can examine what your function returns by calling it in the cell. If you have questions
# about the assignment formats, check out the discussion forums for any FAQs
answer_zero()
# ### Question 1
# Which country has won the most gold medals in summer games?
#
# *This function should return a single string value.*
# In[3]:
def answer_one():
return df['Gold'].idxmax()
answer_one()
# ### Question 2
# Which country had the biggest difference between their summer and winter gold medal counts?
#
# *This function should return a single string value.*
# In[4]:
def answer_two():
return ((df['Gold'] - df['Gold.1']).idxmax())
answer_two()
# ### Question 3
# Which country has the biggest difference between their summer gold medal counts and winter gold medal counts relative to their total gold medal count?
#
# $$\frac{Summer~Gold - Winter~Gold}{Total~Gold}$$
#
# Only include countries that have won at least 1 gold in both summer and winter.
#
# *This function should return a single string value.*
# In[5]:
def answer_three():
only_gold = df.where((df['Gold'] > 0) & (df['Gold.1'] > 0))
only_gold = only_gold.dropna()
return (abs((only_gold['Gold'] - only_gold['Gold.1']) / only_gold['Gold.2'])).idxmax()
answer_three()
# ### Question 4
# Write a function that creates a Series called "Points" which is a weighted value where each gold medal (`Gold.2`) counts for 3 points, silver medals (`Silver.2`) for 2 points, and bronze medals (`Bronze.2`) for 1 point. The function should return only the column (a Series object) which you created.
#
# *This function should return a Series named `Points` of length 146*
# In[66]:
def answer_four():
df['Points'] = (df['Gold.2'] * 3 + df['Silver.2'] * 2 + df['Bronze.2'] * 1)
return df['Points']
answer_four()
# ## Part 2
# For the next set of questions, we will be using census data from the [United States Census Bureau](http://www.census.gov/popest/data/counties/totals/2015/CO-EST2015-alldata.html). Counties are political and geographic subdivisions of states in the United States. This dataset contains population data for counties and states in the US from 2010 to 2015. [See this document](http://www.census.gov/popest/data/counties/totals/2015/files/CO-EST2015-alldata.pdf) for a description of the variable names.
#
# The census dataset (census.csv) should be loaded as census_df. Answer questions using this as appropriate.
#
# ### Question 5
# Which state has the most counties in it? (hint: consider the sumlevel key carefully! You'll need this for future questions too...)
#
# *This function should return a single string value.*
# In[67]:
census_df = pd.read_csv('census.csv')
census_df.head()
# In[68]:
def answer_five():
new_df = census_df[census_df['SUMLEV'] == 50]
return new_df.groupby('STNAME').count()['SUMLEV'].idxmax()
answer_five()
# ### Question 6
# Only looking at the three most populous counties for each state, what are the three most populous states (in order of highest population to lowest population)? Use `CENSUS2010POP`.
#
# *This function should return a list of string values.*
# In[71]:
def answer_six():
new_df = census_df[census_df['SUMLEV'] == 50]
most_populous_counties = new_df.sort_values('CENSUS2010POP', ascending=False).groupby('STNAME').head(3)
return most_populous_counties.groupby('STNAME').sum().sort_values('CENSUS2010POP', ascending=False).head(3).index.tolist()
answer_six()
# ### Question 7
# Which county has had the largest absolute change in population within the period 2010-2015? (Hint: population values are stored in columns POPESTIMATE2010 through POPESTIMATE2015, you need to consider all six columns.)
#
# e.g. If County Population in the 5 year period is 100, 120, 80, 105, 100, 130, then its largest change in the period would be |130-80| = 50.
#
# *This function should return a single string value.*
# In[80]:
def answer_seven():
new_df = census_df[census_df['SUMLEV'] == 50][[6, 9, 10, 11, 12, 13, 14]]
new_df["MaxDiff"] = abs(new_df.max(axis=1) - new_df.min(axis=1))
most_change = new_df.sort_values(by=["MaxDiff"], ascending = False)
return most_change.iloc[0][0]
answer_seven()
# ### Question 8
# In this datafile, the United States is broken up into four regions using the "REGION" column.
#
# Create a query that finds the counties that belong to regions 1 or 2, whose name starts with 'Washington', and whose POPESTIMATE2015 was greater than their POPESTIMATE 2014.
#
# *This function should return a 5x2 DataFrame with the columns = ['STNAME', 'CTYNAME'] and the same index ID as the census_df (sorted ascending by index).*
# In[122]:
def answer_eight():
counties = census_df[census_df['SUMLEV'] == 50]
region = counties[(counties['REGION'] == 1) | (counties['REGION'] == 2)]
washington = region[region['CTYNAME'].str.startswith("Washington")]
grew = washington[washington['POPESTIMATE2015'] > washington['POPESTIMATE2014']]
return grew[['STNAME', 'CTYNAME']]
answer_eight()