Check Armstrong Number of any number of digit

#include<iostream>

#include<math.h>

using namespace std;

int main()

{

    int n,num,rem,i=0;

    float result=0;

    cout<<"Enter the number:"<<endl;

    cin>>n;

    num=n;

    for(num=n;num!=0;++i)        //store the number of digits of n in num

    {

        num/=10;

    }

    for(num=n;num!=0;num/=10)

    {

        rem=num%10;

        result+=pow(rem,i);    //store the sum of power of each digits in result    

    }

    if((int)result==n)

        cout<<"Yes, it is an Armstrong Number";

        else

            cout<<"No, it is not an Armstrong Number";

    return 0;


}