For two strings s
and t
, we say "t
divides s
" if and only if s = t + ... + t
(i.e., t
is concatenated with itself one or more times).
Given two strings str1
and str2
, return the largest string x
such that x
divides both str1
and str2
.
Example 1:
Input: str1 = "ABCABC", str2 = "ABC"
Output: "ABC"
Example 2:
Input: str1 = "ABABAB", str2 = "ABAB"
Output: "AB"
Example 3:
Input: str1 = "LEET", str2 = "CODE"
Output: ""
Constraints:
1 <= str1.length, str2.length <= 1000
str1
andstr2
consist of English uppercase letters. """
Python:
class Solution(object):
def gcd(self, a, b):
while b:
a, b = b, a % b
return a
def gcdOfStrings(self, str1, str2):
"""
:type str1: str
:type str2: str
:rtype: str
"""
len_gcd = self.gcd(len(str1), len(str2))
str_gcd = str1[:len_gcd]
if str_gcd * (len(str1) // len_gcd) == str1 and str_gcd * (len(str2) // len_gcd) == str2:
return str_gcd
else:
return ""