Empty variable expansion in FOR /F statement

[andry81]

Started from: #3

FOR /F "delims=" %%L in (""!string!"") do echo ...%%~L

@jeb-de Found the case where it does not work as expected:

FOR /F "delims=" %%L in (""!string:* =!"") do echo ...%%~L

, where you want to remove everything before the last space and the string can be empty before or after.

@echo off

setlocal

for /F "usebackq tokens=1,* delims=[" %%i in (`@ver 2^>nul`) do for /F "tokens=1,* delims=]" %%k in ("%%j") do set "WINDOWS_VER_STR=%%k"

set WINDOWS_VER_STR

setlocal ENABLEDELAYEDEXPANSION & for /F "tokens=* delims="eol^= %%i in ("!WINDOWS_VER_STR:* =!") do endlocal & set "WINDOWS_VER_STR=%%i"

set WINDOWS_VER_STR

WINDOWS_VER_STR=X.Y.Z

For example, if ver will return something like Microsoft Windows [Version X.Y.Z blabla] or Microsoft Windows [Version X.Y.Z ]

[andry81]

FOR /F "delims=" %%L in (""!string:* =!"") do echo ...%%~L

Workaround:

FOR /F "usebackq delims=" %%L in ('"!string:* =!"') do echo ...%%~L

[jeb-de]

Using usebackq is one way, the other is to escape the outer quotes.

FOR /F "delims=" %%L in (^""!string:* =!"^") do echo ...%%~L