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11.4.5 #20

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alefherrera opened this issue Jun 19, 2020 · 2 comments

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alefherrera commented Jun 19, 2020 •

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alefherrera commented Jun 19, 2020 •

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Xac + Xad + Xbc + Xbd = 1

chrisnlopez commented Jun 30, 2020 •

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Hola Ale, entonces este ejercicio quedaría así?:

min 3Xoa + 6Xob + 6Xac + 5Xad + 4Xbc + 3Xbd + 3Xct + 2Xdt

s.t.
Xoa + Xob = 1 restirccion camino origen
Xct + Xdt = 1 restriccion camino destino
Xac + Xad + Xbc + Xbd = 1 restriccion camino intermedio

Xi binaria

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