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Copy path27. Remove Element.cpp
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27. Remove Element.cpp
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// Given an integer array nums and an integer val, remove all occurrences of val in nums in-place. The order of the elements may be changed. Then return the number of elements in nums which are not equal to val.
// Consider the number of elements in nums which are not equal to val be k, to get accepted, you need to do the following things:
// Change the array nums such that the first k elements of nums contain the elements which are not equal to val. The remaining elements of nums are not important as well as the size of nums.
// Return k.
// Custom Judge:
// The judge will test your solution with the following code:
// int[] nums = [...]; // Input array
// int val = ...; // Value to remove
// int[] expectedNums = [...]; // The expected answer with correct length.
// // It is sorted with no values equaling val.
// int k = removeElement(nums, val); // Calls your implementation
// assert k == expectedNums.length;
// sort(nums, 0, k); // Sort the first k elements of nums
// for (int i = 0; i < actualLength; i++) {
// assert nums[i] == expectedNums[i];
// }
// If all assertions pass, then your solution will be accepted.
// Example 1:
// Input: nums = [3,2,2,3], val = 3
// Output: 2, nums = [2,2,_,_]
// Explanation: Your function should return k = 2, with the first two elements of nums being 2.
// It does not matter what you leave beyond the returned k (hence they are underscores).
// Example 2:
// Input: nums = [0,1,2,2,3,0,4,2], val = 2
// Output: 5, nums = [0,1,4,0,3,_,_,_]
// Explanation: Your function should return k = 5, with the first five elements of nums containing 0, 0, 1, 3, and 4.
// Note that the five elements can be returned in any order.
// It does not matter what you leave beyond the returned k (hence they are underscores).
// Constraints:
// 0 <= nums.length <= 100
// 0 <= nums[i] <= 50
// 0 <= val <= 100
class Solution {
public:
int removeElement(vector<int>& nums, int val) {
int n = nums.size();
int count = 0;
vector<int> ans;
for(int i=0; i<n; i++){
if(nums[i]!=val){
ans.push_back(nums[i]);
count++;
}
}
nums.clear();
for(int i=0; i<ans.size(); i++){
nums.push_back(ans[i]);
}
return count;
}
};