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Copy path1208. Get Equal Substrings Within Budget.cpp
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1208. Get Equal Substrings Within Budget.cpp
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// You are given two strings s and t of the same length and an integer maxCost.
// You want to change s to t. Changing the ith character of s to ith character of t costs |s[i] - t[i]| (i.e., the absolute difference between the ASCII values of the characters).
// Return the maximum length of a substring of s that can be changed to be the same as the corresponding substring of t with a cost less than or equal to maxCost. If there is no substring from s that can be changed to its corresponding substring from t, return 0.
// Example 1:
// Input: s = "abcd", t = "bcdf", maxCost = 3
// Output: 3
// Explanation: "abc" of s can change to "bcd".
// That costs 3, so the maximum length is 3.
// Example 2:
// Input: s = "abcd", t = "cdef", maxCost = 3
// Output: 1
// Explanation: Each character in s costs 2 to change to character in t, so the maximum length is 1.
// Example 3:
// Input: s = "abcd", t = "acde", maxCost = 0
// Output: 1
// Explanation: You cannot make any change, so the maximum length is 1.
// Constraints:
// 1 <= s.length <= 105
// t.length == s.length
// 0 <= maxCost <= 106
// s and t consist of only lowercase English letters.
class Solution {
public:
int equalSubstring(string s, string t, int maxCost) {
int n = s.size();
int start = 0;
int current_cost = 0;
int max_length = 0;
for (int end = 0; end < n; ++end) {
current_cost += abs(s[end] - t[end]);
while (current_cost > maxCost) {
current_cost -= abs(s[start] - t[start]);
++start;
}
max_length = max(max_length, end - start + 1);
}
return max_length;
}
};