logical_calculator.md

Logical calculator

Description

Your Task

Given an array of Boolean values and a logical operator, return a Boolean result based on sequentially applying the operator to the values in the array.

Examples

1. booleans = [True, True, False], operator = "AND"

• True AND True -> True
• True AND False -> False
• return False

2. booleans = [True, True, False], operator = "OR"

• True OR True -> True
• True OR False -> True
• return True

3. booleans = [True, True, False], operator = "XOR"

• True XOR True -> False
• False XOR False -> False
• return False

Input

1. an array of Boolean values (1 <= array_length <= 50)
2. a string specifying a logical operator: "AND", "OR", "XOR"

Output

A Boolean value (True or False).

My Solution

def logical_calc(array, op)
   case op
   when "AND"
      array.all?
   when "OR"
      array.any?
   when "XOR"
      array.count(true) % 2 != 0
   end
end

Better/Alternative solution from Codewars

def logical_calc(arr, op)
  op=='AND' ? arr.reduce(:&) : op=='OR' ? arr.reduce(:|) : arr.reduce(:^)
end