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719. Find K-th Smallest Pair Distance
这道题我一开始想用堆来做,但发现绕不开pair,因为要遍历所有的pair,这样肯定不行的。
那么就要换另一种做法了。我要向另一种方法巧妙地绕过pair的限制,不需要遍历所有的pair,也就是说,只有一次遍历。(Sliding Window?
根据我们已有的条件,我们有数组,有最大距离,最小距离,有k值,所以也就想到二分法结合滑动窗口去逼近k。
Time: O(nlogn + mlogm) Space: O(1)
class Solution { public int smallestDistancePair(int[] nums, int k) { int n = nums.length; Arrays.sort(nums); int r = nums[n - 1] - nums[0] + 1; int l = r; for (int i = 1; i < n; i++) { l = Math.min(l, nums[i] - nums[i - 1]); } while (l < r) { int m = (l + r) >> 1; if (countWithin(nums, n, m) >= k) { r = m; } else { l = m + 1; } } return l; } private int countWithin(final int[] nums, final int n, int m) { int ll = 0, rr = 1, cnt = 0; while (rr < n) { while (ll < rr && nums[rr] - nums[ll] > m) { ll++; } cnt += (rr - ll); rr++; } return cnt; } }
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Leetcode 719. Find K-th Smallest Pair Distance
719. Find K-th Smallest Pair Distance
Institution
这道题我一开始想用堆来做,但发现绕不开pair,因为要遍历所有的pair,这样肯定不行的。
那么就要换另一种做法了。我要向另一种方法巧妙地绕过pair的限制,不需要遍历所有的pair,也就是说,只有一次遍历。(Sliding Window?
根据我们已有的条件,我们有数组,有最大距离,最小距离,有k值,所以也就想到二分法结合滑动窗口去逼近k。
Complexity
Time: O(nlogn + mlogm)
Space: O(1)
Code
The text was updated successfully, but these errors were encountered: