https://leetcode.com/explore/challenge/card/30-day-leetcoding-challenge/529/week-2/3293/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int diameterOfBinaryTree(TreeNode* root) {
helper(root);
return FindMaxValue(root);
}
public:
int helper(TreeNode* root) {
if (root == NULL) {
return 0;
}
int left = helper(root->left);
int right = helper(root->right);
root->val = left + right;
return max(left, right) + 1;
}
int FindMaxValue(TreeNode* root) {
if (root == NULL) {
return 0;
}
int left = FindMaxValue(root->left);
int right = FindMaxValue(root->right);
left = max(left, right);
return max(left, root->val);
}
};
- Use member variable
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int max_diameter = 0;
int diameterOfBinaryTree(TreeNode* root) {
FindMaxDiameter(root);
return max_diameter;
}
public:
int FindMaxDiameter(TreeNode* root) {
if (root == NULL) {
return 0;
}
int left = FindMaxDiameter(root->left);
int right = FindMaxDiameter(root->right);
max_diameter = max(max_diameter, left + right);
return max(left, right) + 1;
}
};