task1.4.ipynb

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   "source": [
    "# <a id=\"#\">Task 1.4 – Writing loops in Python</a>"
   ]
  },
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   "source": [
    "**<a id=\"#\">Task 1.4.1.</a>** Use a `while`-loop to write the numbers from 5 to 15.\n",
    "\n",
    "**Hint:** The Syntax of a `while`-loop is\n",
    "```python\n",
    "while condition:\n",
    "    operation\n",
    "```\n",
    "\n",
    "Example:\n",
    "```python\n",
    "i = 0\n",
    "while i < 10:\n",
    "    print(i)\n",
    "    i = i + 1\n",
    "```\n",
    "\n",
    "**Hint:** Variables and text can be printed using `print`, for example:\n",
    "```python\n",
    "print(i)\n",
    "print('The result is i=' + str(i))\n",
    "```\n",
    "\n",
    "**Hint:** If your code cell keeps running seemingly forever, you have probably produced an *infinite loop*. In that case, you can interrupt the execution of the code cell by clicking the □ button which appears right to the left of the executed cell, and then fix the problem. If the □ button does not appear, try clicking the cell first!"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "0\n",
      "the result is i=0\n"
     ]
    }
   ],
   "source": [
    "i=0\n",
    "while i < 0:\n",
    "    print(i)\n",
    "    i = i + 1\n",
    "print(i)\n",
    "print('the result is i=' + str(i))"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "<div class=\"alert alert-block alert-success\"><b>Hint:</b> Now might be a good moment to commit and push your progress :) preferably, you should be doing this <em>at least</em> after completing each task. It doesn't harm if you do it sometimes in between too, e.g., when you feel like you have had some significant progress with a task.</div>"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**<a id=\"#\">Task 1.4.2.</a>** Use a `while`-loop to compute and write the squares of the numbers from 1 to 20. The result should be shown like:\n",
    "```\n",
    "1 -> 1\n",
    "2 -> 4\n",
    "3 -> 9\n",
    "…\n",
    "20 -> 400\n",
    "```\n",
    "**Hint:** Square of a number `i` can be computed by `i ** 2` or `i * i`."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "i--> 1\n",
      "i--> 4\n",
      "i--> 9\n",
      "i--> 16\n",
      "i--> 25\n",
      "i--> 36\n",
      "i--> 49\n",
      "i--> 64\n",
      "i--> 81\n",
      "i--> 100\n",
      "i--> 121\n",
      "i--> 144\n",
      "i--> 169\n",
      "i--> 196\n",
      "i--> 225\n",
      "i--> 256\n",
      "i--> 289\n",
      "i--> 324\n",
      "i--> 361\n",
      "i--> 400\n"
     ]
    }
   ],
   "source": [
    "i=1\n",
    "while i<21:\n",
    " print ('i-->',i*i)\n",
    " i+=1"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**<a id=\"#\">Task 1.4.3.</a>** Copy your solution from **Task 1.4.2** and modify the code such that *the squares are only computed for even numbers*."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "i--> 4\n",
      "i--> 16\n",
      "i--> 36\n",
      "i--> 64\n",
      "i--> 100\n",
      "i--> 144\n",
      "i--> 196\n",
      "i--> 256\n",
      "i--> 324\n",
      "i--> 400\n"
     ]
    }
   ],
   "source": [
    "i=1\n",
    "while i<21:\n",
    " if ( i % 2)==0:\n",
    "    print ('i-->',i*i)\n",
    " i+=1"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**<a id=\"#\">Task 1.4.4.</a>** Use a `for`-loop to compute the sum of the numbers from 1 to 100. The correct result would be 5050.\n",
    "\n",
    "**Hint:** The Syntax of a `for`-loop is\n",
    "```python\n",
    "for i in iterable:\n",
    "    operation\n",
    "```\n",
    "\n",
    "Example:\n",
    "```python\n",
    "for i in [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]:\n",
    "    print(i)\n",
    "```\n",
    "\n",
    "**Hint:** An `iterable` sequence of numbers from `i` (inclusive) to `j` (exclusive) can be constructed using `range(i, j)`."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
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      "5050\n",
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      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n",
      "5050\n"
     ]
    }
   ],
   "source": [
    "n=range(1,101)\n",
    "for i in n:\n",
    "    print(sum(n))\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**<a id=\"#\">Task 1.4.5.</a>** Generate the times table (\"Kleines Einmaleins\") by using two nested for loops, i.e., using an outer and an inner loop. The result should be shown like:\n",
    "```\n",
    "1 2 3 … 10\n",
    "2 4 6 … 20\n",
    "3 6 9 … 30\n",
    "…\n",
    "10 20 30 … 100\n",
    "```\n",
    "\n",
    "**Hint:** The function `print(s, end='')` works like `print(s)` but does *not* append a line break (as `print(s)` does)."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "01 02 03 04 05 06 07 08 09 10  \n",
      "02 04 06 08 10 12 14 16 18 20  \n",
      "03 06 09 12 15 18 21 24 27 30  \n",
      "04 08 12 16 20 24 28 32 36 40  \n",
      "05 10 15 20 25 30 35 40 45 50  \n",
      "06 12 18 24 30 36 42 48 54 60  \n",
      "07 14 21 28 35 42 49 56 63 70  \n",
      "08 16 24 32 40 48 56 64 72 80  \n",
      "09 18 27 36 45 54 63 72 81 90  \n",
      "10 20 30 40 50 60 70 80 90 100  \n"
     ]
    }
   ],
   "source": [
    "for i in range (1,11):\n",
    "    for j in range (1,11):\n",
    "        k=i*j\n",
    "        if k < 10:\n",
    "            k=\"0\"+str(k)\n",
    "        print (k, end=' ')\n",
    "    print (\" \")\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 11,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "1 2 3 4 5 6 7 8 9 10  \n",
      "2 4 6 8 10 12 14 16 18 20  \n",
      "3 6 9 12 15 18 21 24 27 30  \n",
      "4 8 12 16 20 24 28 32 36 40  \n",
      "5 10 15 20 25 30 35 40 45 50  \n",
      "6 12 18 24 30 36 42 48 54 60  \n",
      "7 14 21 28 35 42 49 56 63 70  \n",
      "8 16 24 32 40 48 56 64 72 80  \n",
      "9 18 27 36 45 54 63 72 81 90  \n",
      "10 20 30 40 50 60 70 80 90 100  \n"
     ]
    }
   ],
   "source": [
    "for i in range (1,11):\n",
    "    for j in range (1,11):\n",
    "        k=i*j\n",
    "        print(k,end=' ')\n",
    "    print(\" \")"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "**<a id=\"#\">Task 1.4.6.</a>** Copy your solution from **Task 1.4.5** and modify the code such that *values below 10 in the times table have a leading zero* (e.g., `05` instead of only `5`). This can be achieved, for example, by using an `if`-statement.\n",
    "\n",
    "**Hint:** The Syntax of an `if`-statement is\n",
    "```python\n",
    "if condition:\n",
    "    operation1\n",
    "else:\n",
    "    operation2\n",
    "```\n",
    "\n",
    "Example:\n",
    "```python\n",
    "if val < 5:\n",
    "    print('val is less than 5')\n",
    "else:\n",
    "    print('val is larger or equal 5')\n",
    "```"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
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