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26.remove-duplicates-from-sorted-array.cs
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/*
* @lc app=leetcode id=26 lang=csharp
*
* [26] Remove Duplicates from Sorted Array
*
* https://leetcode.com/problems/remove-duplicates-from-sorted-array/description/
*
* algorithms
* Easy (44.40%)
* Likes: 2431
* Dislikes: 4984
* Total Accepted: 950.2K
* Total Submissions: 2.1M
* Testcase Example: '[1,1,2]'
*
* Given a sorted array nums, remove the duplicates in-place such that each
* element appear only once and return the new length.
*
* Do not allocate extra space for another array, you must do this by modifying
* the input array in-place with O(1) extra memory.
*
* Example 1:
*
*
* Given nums = [1,1,2],
*
* Your function should return length = 2, with the first two elements of nums
* being 1 and 2 respectively.
*
* It doesn't matter what you leave beyond the returned length.
*
* Example 2:
*
*
* Given nums = [0,0,1,1,1,2,2,3,3,4],
*
* Your function should return length = 5, with the first five elements of nums
* being modified to 0, 1, 2, 3, and 4 respectively.
*
* It doesn't matter what values are set beyond the returned length.
*
*
* Clarification:
*
* Confused why the returned value is an integer but your answer is an array?
*
* Note that the input array is passed in by reference, which means
* modification to the input array will be known to the caller as well.
*
* Internally you can think of this:
*
*
* // nums is passed in by reference. (i.e., without making a copy)
* int len = removeDuplicates(nums);
*
* // any modification to nums in your function would be known by the caller.
* // using the length returned by your function, it prints the first len
* elements.
* for (int i = 0; i < len; i++) {
* print(nums[i]);
* }
*/
namespace _26
{
// @lc code=start
public class Solution
{
public int RemoveDuplicates(int[] nums)
{
if (nums.Length < 2)
{
return nums.Length;
}
int j = 1;
var prev = nums[0];
for (int i = 1; i < nums.Length; i++)
{
if (prev != nums[i])
{
nums[j++] = nums[i];
prev = nums[i];
}
}
return j;
}
// public int RemoveDuplicates(int[] nums)
// {
// var end = nums.Length > 1 ? 1 : nums.Length;
// for(int i = 1; i < nums.Length; i++)
// if(nums[i - 1] != nums[i])
// nums[end++] = nums[i];
// return end;
// }
}
// @lc code=end
}