- 涉及到指针和取值一定要多考虑是否为null的情况
class Solution {
public ListNode deleteDuplicates(ListNode head) {
if(head == null || head.next == null)
return head;
ListNode cur = head;
ListNode nex = head.next;
while(nex!=null){
while(nex != null && nex.val == cur.val)//nex 可能为null
nex = nex.next;
cur.next = nex;
cur = nex;
}
return head;
}
}